Can you try this code, if the SESSION is empty:
<?
session_start();
if (empty($_SESSION['username'])){
echo 'Please Log In';
include 'loginform.php';
}else{
echo 'Welcome';
?>
<a href="index.php">Home</a>
<?
}
?>
سؤال
I want to include a link to my logout.php which includes code to destroy the session inside my php on this page how would I do this?
<?php
if (isset($_SESSION['username'])) {
echo 'Welcome';
"<a href="logout.php">Logout</a>";
} else {
include 'loginform.php';
echo 'Please Log In';
}
?>
المحلول
Can you try this code, if the SESSION is empty:
<?
session_start();
if (empty($_SESSION['username'])){
echo 'Please Log In';
include 'loginform.php';
}else{
echo 'Welcome';
?>
<a href="index.php">Home</a>
<?
}
?>
نصائح أخرى
Before you use any $_SESSION variable, you have to call session_start()
The logout should first open the session by calling session_start()
, then destroy it by calling session_destroy
You aren't currently telling PHP to display the link to the logout page. It either needs to be included in the echo
or outputted elsewhere. For example;
if (isset($_SESSION['username'])) {
echo 'Welcome';
echo '<a href="logout.php">Logout</a>';
}
else {
include 'loginform.php';
echo 'Please Log In';
}
In your logout.php put this code ,
<?php
session_start();
session_destroy();
?>