Query to show two columns of single column from table

Question

I need some help with query writing. I have a table as in SQLFiddle:

http://sqlfiddle.com/#!2/7f51a

I need a result set as below, i.e: The query should show three columns, first is name,second is 'One' and third is 'two'. It shows data in col 'one' only if that name has value 'one' in tbl1 else it should stay blank. Similary third column should show value only if 'Name' has corresponding 'two'value.

Name    |   One |   Two
--------+-------+----------
Jig     |   Yes |   Yes  
Mig     |       |   Yes  
Dig     |   Yes |   

Answer 1

Try this:

SELECT Name,
      IFNULL(MAX(CASE WHEN Book ='one' THEN 'Yes' END),'') as One,
      IFNULL(MAX(CASE WHEN Book='two' THEN 'Yes' END),'') as Two
FROM tbl1
GROUP BY Name

NB: For oracle, use NVL instead of IFNULL.

Result:

NAME    ONE   TWO
Dig     Yes 
Jig     Yes   Yes
Mig           Yes

Fiddle here.

Answer 2

Using Pivot in 11g+ and above:

select *
  from tbl1
  pivot (max('Yes') for book in ('one' as one, 'two' as two) );

output:

| NAME |    ONE |    TWO |
|------|--------|--------|
|  Dig |    Yes | (null) |
|  Jig |    Yes |    Yes |
|  Mig | (null) |    Yes |

Sqlfiddle : http://sqlfiddle.com/#!4/d09cf9/1

Answer 3

You can use the Query

select * from tbl1;



select name
      ,max(decode(book,'one','yes','-')) as one
      ,max(decode(book,'two','yes','-')) as two

      from tbl1

group by name;