How to get the index of a maximum element in a numpy array along one axis
سؤال
I have a 2 dimensional NumPy array. I know how to get the maximum values over axes:
>>> a = array([[1,2,3],[4,3,1]])
>>> amax(a,axis=0)
array([4, 3, 3])
How can I get the indices of the maximum elements? So I would like as output array([1,1,0])
المحلول
>>> a.argmax(axis=0)
array([1, 1, 0])
نصائح أخرى
>>> import numpy as np
>>> a = np.array([[1,2,3],[4,3,1]])
>>> i,j = np.unravel_index(a.argmax(), a.shape)
>>> a[i,j]
4
argmax()
will only return the first occurrence for each row.
http://docs.scipy.org/doc/numpy/reference/generated/numpy.argmax.html
If you ever need to do this for a shaped array, this works better than unravel
:
import numpy as np
a = np.array([[1,2,3], [4,3,1]]) # Can be of any shape
indices = np.where(a == a.max())
You can also change your conditions:
indices = np.where(a >= 1.5)
The above gives you results in the form that you asked for. Alternatively, you can convert to a list of x,y coordinates by:
x_y_coords = zip(indices[0], indices[1])
v = alli.max()
index = alli.argmax()
x, y = index/8, index%8
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