Query to find all dates between two specified dates using plsql
https://dba.stackexchange.com/questions/285087
-
15-03-2021 - |
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I have a table with below structure
create table test_table
(
customer_num NUMBER,
card_number char(2),
card_issue_date DATE,
card_expire_date DATE
)
Example data is:
customer_num | card_number | card_issue_date | card_expire_date
--------------------------------------------------------------------------
1 | x | 1/1/2019 | 1/4/2020
1 | y | 1/1/2020 | 1/4/2020
1 | z | 1/11/2020 | 1/15/2020
1 | b | 1/11/2020 | 1/20/2020
1 | w | 1/12/2020 | 1/17/2020
1 | a | 1/18/2020 | 2/12/2020
For each customer's card, I need to have all dates between card_issue_date and card_expire_date.
So the output for the first record would be like this :
customer_num | card_number | card_issue_date
----------------------------------------------------
1 | x | 1/1/2019
1 | x | 1/2/2020
1 | x | 1/3/2020
1 | x | 1/4/2020
IS there any function or something else that can help me out with this?
Thanks in advance
المحلول
This should get you started:
declare
s date := date'2020-01-01';
e date := date'2020-01-04';
ndays number;
begin
ndays := e-s+1;
for i in 1..ndays loop
dbms_output.put_line (s);
s := s+1;
end loop;
end;
/
01-JAN-2020
02-JAN-2020
03-JAN-2020
04-JAN-2020
PL/SQL procedure successfully completed.
Just use simple date arithmetic: the difference between two dates is the number of days between the two:
date'2020-01-04' - date'2020-01-01' + 1
The above returns 4 (the +1 is so as to also include the last day, since this is what you describe in your example).
Then the rest is just a loop over the number of days, incrementing the start date by one day on each loop:
s := s + 1;
The next stage is to turn that into a usable function. First we need a type:
create or replace type date_array as table of date;
/
This defines an array of dates as is used as the output of the pipelined function:
create or replace function dates_between (s date, e date)
return date_array
pipelined
is
d date := s;
begin
for i in 1..e-s+1 loop
pipe row(d);
d := d + 1;
end loop;
end;
/
show errors
This function returns the list of dates between two dates (including the end date). Like this:
SQL> select * from table (dates_between (date'2020-02-23',date'2020-03-05'));
COLUMN_VALUE
-----------------
23-FEB-2020
24-FEB-2020
25-FEB-2020
26-FEB-2020
27-FEB-2020
28-FEB-2020
29-FEB-2020
01-MAR-2020
02-MAR-2020
03-MAR-2020
04-MAR-2020
05-MAR-2020
12 rows selected.
Let's try that with your example. First let's create and populate the test table:
drop table test_table purge;
create table test_table (
customer_num NUMBER,
card_number char(2),
card_issue_date DATE,
card_expire_date DATE
);
insert into test_table values (1,'x',to_date('1/1/2020 ','MM-DD-YYYY') ,to_date('1/4/2020','MM-DD-YYYY'));
insert into test_table values (1,'y',to_date('1/1/2020 ','MM-DD-YYYY') ,to_date('1/4/2020','MM-DD-YYYY'));
insert into test_table values (1,'z',to_date('1/11/2020','MM-DD-YYYY') ,to_date('1/15/2020','MM-DD-YYYY'));
insert into test_table values (1,'b',to_date('1/11/2020','MM-DD-YYYY') ,to_date('1/20/2020','MM-DD-YYYY'));
insert into test_table values (1,'w',to_date('1/12/2020','MM-DD-YYYY') ,to_date('1/17/2020','MM-DD-YYYY'));
insert into test_table values (1,'a',to_date('1/18/2020','MM-DD-YYYY') ,to_date('2/12/2020','MM-DD-YYYY'));
commit;
(Noticed I corrected the first date to match your description).
Here is the query that gives the result you describe:
select customer_num, card_number, column_value as card_date
from test_table, table (dates_between (card_issue_date,card_expire_date));
which returns:
CUSTOMER_NUM CARD_N CARD_DATE
------------ ------ -----------------
1 x 01-JAN-2020
1 x 02-JAN-2020
1 x 03-JAN-2020
1 x 04-JAN-2020
1 y 01-JAN-2020
1 y 02-JAN-2020
1 y 03-JAN-2020
1 y 04-JAN-2020
1 z 11-JAN-2020
1 z 12-JAN-2020
1 z 13-JAN-2020
1 z 14-JAN-2020
1 z 15-JAN-2020
1 b 11-JAN-2020
1 b 12-JAN-2020
1 b 13-JAN-2020
1 b 14-JAN-2020
1 b 15-JAN-2020
1 b 16-JAN-2020
1 b 17-JAN-2020
1 b 18-JAN-2020
1 b 19-JAN-2020
1 b 20-JAN-2020
1 w 12-JAN-2020
1 w 13-JAN-2020
1 w 14-JAN-2020
1 w 15-JAN-2020
1 w 16-JAN-2020
1 w 17-JAN-2020
1 a 18-JAN-2020
1 a 19-JAN-2020
1 a 20-JAN-2020
1 a 21-JAN-2020
1 a 22-JAN-2020
1 a 23-JAN-2020
1 a 24-JAN-2020
1 a 25-JAN-2020
1 a 26-JAN-2020
1 a 27-JAN-2020
1 a 28-JAN-2020
1 a 29-JAN-2020
1 a 30-JAN-2020
1 a 31-JAN-2020
1 a 01-FEB-2020
1 a 02-FEB-2020
1 a 03-FEB-2020
1 a 04-FEB-2020
1 a 05-FEB-2020
1 a 06-FEB-2020
1 a 07-FEB-2020
1 a 08-FEB-2020
1 a 09-FEB-2020
1 a 10-FEB-2020
1 a 11-FEB-2020
1 a 12-FEB-2020
55 rows selected.
نصائح أخرى
Using just SQL and using Tom's as_many_rows trick(adjust as required):
with as_many_rows_as_you_need
as
( select level l
from dual
connect by level <= 100
)
select customer_num cust, card_number card, (a.card_issue_date + l) dat
from as_many_rows_as_you_need
, test_table a
where a.card_issue_date + l <= a.card_expire_date
and a.customer_num = 1
--and a.card_number = 'x'
order by card_number, (a.card_issue_date + l)
;
Using above table definition and data, results in(cut-off...):
CUST CARD DAT
1 a 19-jan-20
1 a 20-jan-20
1 a 21-jan-20
1 b 12-jan-20
1 b 13-jan-20
1 b 14-jan-20
1 b 15-jan-20
1 b 16-jan-20
1 b 17-jan-20
1 b 18-jan-20
1 b 19-jan-20
1 b 20-jan-20
1 w 13-jan-20
1 w 14-jan-20
1 w 15-jan-20
1 w 16-jan-20
1 w 17-jan-20
...
