Calculate what the date will be based on startdate and value using PHP skip weekends
سؤال
I have a startdate, let's say this is $startDate = 2012-08-01;
and I have a variable that stores an INT value, lets say this is $value = 10;
I would like to calculate what the date would be from startdate + 10 days and skip weekends.
Using the above values the result would be 2012-08-15
How would this be done?
المحلول
This is far from efficient, but who cares about that right when it is readable? :)
<?php
function calculateNextDate($startDate, $days)
{
$dateTime = new DateTime($startDate);
while($days) {
$dateTime->add(new DateInterval('P1D'));
if ($dateTime->format('N') < 6) {
$days--;
}
}
return $dateTime->format('Y-m-d');
}
echo calculateNextDate('2012-08-01', 10); // return 2012-08-15
What happens should be pretty easy to follow. First we create a new DateTime
object using the date provided by the user. After that we are looping through the days we want to add to the date. When we hit a day in the weekend we don't subtract a day from the days we want to add to the date.
نصائح أخرى
you can use php's strtotime function to + n days/hours etc..,
and for excluding weekends have a look here: 32 hours ago excluding weekends with php
Try this
<?php
function businessdays($begin, $end) {
$rbegin = is_string($begin) ? strtotime(strval($begin)) : $begin;
$rend = is_string($end) ? strtotime(strval($end)) : $end;
if ($rbegin < 0 || $rend < 0)
return 0;
$begin = workday($rbegin, TRUE);
$end = workday($rend, FALSE);
if ($end < $begin) {
$end = $begin;
$begin = $end;
}
$difftime = $end - $begin;
$diffdays = floor($difftime / (24 * 60 * 60)) + 1;
if ($diffdays < 7) {
$abegin = getdate($rbegin);
$aend = getdate($rend);
if ($diffdays == 1 && ($astart['wday'] == 0 || $astart['wday'] == 6) && ($aend['wday'] == 0 || $aend['wday'] == 6))
return 0;
$abegin = getdate($begin);
$aend = getdate($end);
$weekends = ($aend['wday'] < $abegin['wday']) ? 1 : 0;
} else
$weekends = floor($diffdays / 7);
return $diffdays - ($weekends * 2);
}
function workday($date, $begindate = TRUE) {
$adate = getdate($date);
$day = 24 * 60 * 60;
if ($adate['wday'] == 0) // Sunday
$date += $begindate ? $day : -($day * 2);
return $date;
}
$def_date="";//define your date here
$addDay='5 days';//no of previous days
date_add($date, date_interval_create_from_date_string($addDay));
echo businessdays($date, $def_date); //date prior to another date
?>
Modified from PHP.net
if you just want to add up a date +10, you may wanna consider this:
date("Y-m-d", strtotime("+10 days"));