You need to put a variable in the for loop for a complete expression (which is probably line 9...)
for( i = 1; < 10000000; i++)
change to this
for( i = 1; i < 10000000; i++)
سؤال
I am following an example from CUNY and I have never done anything with C before so I probably don't know what I am doing.
Consider the program below.
When I go to compile using the line gcc -g -o forwardadding forwardadding.c
I am hit with the message:
forwardadding.c:9:17: error: expected expression before ‘<’ token
Once I get the code compiles, I can use gdb to debug and run the code corrrect?
The code:
#include <stdio.h>
#include <math.h>
main()
{
float sum, term;
int i;
sum = 0.0;
for( i = 1; < 10000000; i++)
{
term = (float) i;
term = term * term;
term = 1 / term;
sum += term;
}
printf("The sum is %.12f\n", sum);
}
المحلول 2
You need to put a variable in the for loop for a complete expression (which is probably line 9...)
for( i = 1; < 10000000; i++)
change to this
for( i = 1; i < 10000000; i++)
نصائح أخرى
No shebang is needed. You could add an Emacs mode line comment.
The for
loop should be:
for (i = 1; i < 10000000; i++)
Your code is missing the second i
.
Yes, you can use GDB once you've got the code compiling.
You'd get a better answer to the mathematics if you counted down from 10,000,000 than by counting up to 10,000,000. After about i = 10000
, the extra values add nothing to the result.
Please get into the habit of writing C99 code. That means you should write:
int main(void)
with the return type of int
being required and the void
being recommended.
You are missing an an i
. Just correct that as Jonathan Leffler has suggested and save your file. Open your terminal and just use this to compile your code gcc your_file_name.c
and your code compiles next to run the code that just compiled type ./a.out
and your program runs and shows you the output.