كيف يمكنني استخدام Find للنسخ الاحتياطي بشكل متكرر مستودعات تخريب متعددة

Question

في الوقت الحالي ، يدير البرنامج النصي النسخ الاحتياطي بشكل صريح svnadmin hotcopy على كل من مستودعاتنا كل ليلة. يتم تخزين جميع عمليات إعادة التجهيز لدينا تحت دليل الوالدين (/usr/local/svn/repos) البرنامج النصي الاحتياطي لدينا خط لكل من repos تحت هذا الدليل على غرار: svnadmin hotcopy/usr/local/svn/repos/myrepo1 /usr/local/backup/myrepo1

بدلاً من الاضطرار إلى إضافة سطر جديد يدويًا لكل ريبو جديد نحضره عبر الإنترنت ، كنت آمل في استخدام أمر Find لتشغيل svnadmin hotcopy لكل دليل يجده تحت/usr/local/svn/repos.

حتى الآن لدي:

find /usr/local/svn/repos/ -maxdepth 1 -mindepth 1 -type d -exec echo /usr/local/backup{} \;

، حيث أقوم باستبدال "svnadmin hotcopy" مع "Echo" من أجل البساطة. إخراجها هو:

/usr/local/backup/usr/local/svn/repos/ure
/usr/local/backup/usr/local/svn/repos/cheetah
/usr/local/backup/usr/local/svn/repos/casemgt
/usr/local/backup/usr/local/svn/repos/royalliver
/usr/local/backup/usr/local/svn/repos/ure_andras
/usr/local/backup/usr/local/svn/repos/profserv
/usr/local/backup/usr/local/svn/repos/frontoffice
/usr/local/backup/usr/local/svn/repos/ure.orig
/usr/local/backup/usr/local/svn/repos/projectcommon
/usr/local/backup/usr/local/svn/repos/playground
/usr/local/backup/usr/local/svn/repos/casegen

يتم تضمين المشكلة كونها المسار الكامل في {}. أحتاج فقط العنصر الأخير من اسم الدليل إلى -exec

الإخراج الذي أريد أن أكون:

/usr/local/backup/ure
/usr/local/backup/cheetah
/usr/local/backup/casemgt
/usr/local/backup/royalliver
/usr/local/backup/ure_andras
/usr/local/backup/profserv
/usr/local/backup/frontoffice
/usr/local/backup/ure.orig
/usr/local/backup/projectcommon
/usr/local/backup/playground
/usr/local/backup/casegen

أنا عالق إلى حد كبير في هذه المرحلة. هل يمكن لأي شخص مساعدتي هنا؟ شكرا مقدما ، ديف

Answer 1

You were on the right track. Try this:

find /usr/local/svn/repos/ -maxdepth 1 -mindepth 1 -type d -printf "%f\0" | xargs -0 -I{} echo svnadmin hotcopy /usr/local/svn/repos/\{\} /usr/local/backup/\{\}

The %f is like basename and the null plus the -0 on xargs ensures that names with spaces, etc., get passed through successfully.

Just remove the echo and make any adjustments you might need and it should do the trick.

Answer 2

put a cut command at the end

find /usr/local/svn/repos/ -maxdepth 1 -mindepth 1 -type d -exec echo /usr/local/backup{} \| cut -f1,2,3,9 -d"/"

Answer 3

How about adding a sed filter cuting out the middle part?

sed 's/usr.local.svn.repos.//g'

Added like this

find /usr/local/svn/repos/ -maxdepth 1 -mindepth 1 -type d -exec echo /usr/local/backup{} ";" | sed 's/usr.local.svn.repos.//g'

Answer 4

ls -al /usr/local/svn/repos/ |grep '^d' |sed s/^...............................................................//" |xargs -L 1 -I zzyggy echo /usr/local/svn/repos/zzyggy

It's a bit long but it does the trick. You don't have to do everything with find when there are lots of other shell commands, although if I had to write this kind of script, I would do it in Python and leave the shell for interactive work.

ls -al lists all the files in the named directory with attributes

grep '^d' selects the lines beginning with d which are directories

sed strips off all the characters to the left of the actual directory name. You may need to add or delete some dots

xargs takes the list of directory names and issues it one at a time. I specified zzyggy as the name to substitute in the executed command, but you can choose what you like. Of course, you would replace echo with your svnadmin command.

If it was in a shell script you should really do this

SVNDIRNAME="/usr/local/svn/repos"
ls -al $SVNDIRNAME |grep '^d' |sed s/^...............................................................//" |xargs -L 1 -I zzyggy echo $SVNDIRNAME/zzyggy

but I decided to show the wrong and right way just to explain this point. I'm going to tag this with some shell tag, but I still think that a Python script is a superior way to solve this kind of problem in the 21st century.