سؤال

I am learning the bash environment and cannot understand what I get when running this command:

wc filename.txt &

It returns an array with a 1-digital integer and another integer, neither of them matches any other result I can get from wc commands (-l, -m, -w, -c). Besides the second integer is much bigger than for example the bytes counts. So I terribly wonder. I browsed forums and found some explanations on the multiple uses of the ampersand in a Unix/Linux environment, but there was nothing that I could relate. I don't need it, but I won't flush this mystery away, I wish to understand! Thanks

هل كانت مفيدة؟

المحلول

I imagine the integers you see are similar to this:

[1] 1830

& launches a command in the background, and the shell prints its job number (1) and process id (1830). On a longer-running job, you can use those two numbers to control its execution. See the JOB CONTROL section of the bash man page for more details.

نصائح أخرى

An ampersand at the end of a WC command tells the shell to start executing the command in the background and to get ready for further command line commands.

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