Regex : Phone number starting with 06 or 07

Question

I have this function which works only for 10 digits.

function telValide( tel )
{
    var reg = new RegExp('^[0-9]{10}$', 'i');
    return reg.test(tel);
}

I would like to check phone number starting with 06 or 07.

Ex :

06 01010101 : true

07 01240101 : true

00 04343000 : false

Answer 1

var reg = new RegExp('^((06)|(07))[0-9]{8}$', 'i');

Answer 2

I guess it's a simple case:

^0[67][0-9]{8}$

Answer 3

'^0(6|7) [0-9]{8}$'

Or if you mean you want the numbers without a space:

'^0(6|7)[0-9]{8}$'

Check out some excellent regex tutorials here and here.

Answer 4

The easiest pattern would probably be

^0[67]\d{8}$

i.e.

• 0
• 6 or 7
• a digit
• repeated exactly eight times

That assumes that your white space is merely for emphasis.

You could also be fancy and use a lookahead

^(?=0[67])\d{10}+$

This isn't really adding much expect complexity however.

Answer 5

Try it /^\(?(\d{3})\)?[- ]?(\d{3})[- ]?(\d{4})$/ and for more details check below links help you how validate your phone and defined specific format

http://www.zparacha.com/phone_number_regex/

http://dzone.com/snippets/regular-expression-validate