Is there a function in python that returns true if all members of an iterable are true?

Question

I'm tryng to learn different ways to do simple things in python, while also learning a bit about some functional practices. I have some numbers that the user inputs, and I want to know if they really are numbers. I've come up with this kind of classic solution:

def foo(list_of_inputs):
    for n in list_of_inputs:
       if not hasattr(n, "real"):
           # some number is not a number!
           return False
    # all are numbers
    return True

But then, I figured out this other "thing" that may have some potential:

def foo(list_of_inputs):
    bool_list = map(lambda input: hasattr(input, "real"), list_of_inputs)
    return reduce(lambda x, y: x == y, bool_list)

I think that maybe a function that returns "True" if all members of a collection, iterable, or whatever the correct concept I'm looking for, are "True", may already be something somewhat common, and also, this second attempt doesn't return when a "False" is found, while the classic one does... But I find it elegant, and maybe that is because I'm not there yet with programming in general.

So my question is: what's the "probably better" way to do this?

Answer 1

As mentioned, the all function will do what you want. What you describe you're trying to do can also be done with the str.isnumeric() function.

def foo(listOfInputs):
    return all(map(str.isnumeric,listOfInputs))

Edit: I'm finding that it fails on ['1','2','3.14','4'] which is a little annoying. Maybe someone can come up with a cleverer solution than this, but I decided to wrap a slightly modified approach in a try:

def foo(listOfInputs):
    try:
        return all(map(float,listOfInputs))
    except ValueError:
        return False

That works on:

['1','2','-3','4']
['1','2','3.14','4']

Answer 2

You mean something like the built-in all function?

Return True if all elements of the iterable are true (or if the iterable is empty). Equivalent to: