题
我需要访问 topBox 的孙子并确定它们是否是按钮。
下面的这个函数(谢谢 Flextras.com)获取 topBox 的直接子代,即 HBox。我如何才能降低一级到topBox的孙子级?或者唯一的方法是在每个 HBox 上运行此函数?
for (var i : int =0; i<topBox.numChildren; i++){
var child : DisplayObject = topBox.getChildAt(i);
var myButton:UIComponent = child as UIComponent;
blah blah
}
<mx:VBox id="topBox">
<mx:HBox id="Hbox1">
<mx:Button id="button1"
label="button1"
click="myClickHandler"/>
<mx:Button id="button2"
label="button2"
click="myClickHandler"/>
</mx:HBox>
<mx:HBox id="Hbox2">
<mx:Button id="button3"
label="button3"
click="myClickHandler"/>
<mx:Button id="button4"
label="button4"
click="myClickHandler"/>
</mx:HBox>
<mx:VBox>
解决方案
//declare child access function
private function processChildren(target:DisplayObjectContainer, handler:Function):void
{
for (var i:int = target.numChildren - 1; i >= 0; i--)
{
handler(target.getChildAt(i));
}
}
//call it with handler as anonymous function (may be plain one as well)
processChildren(topBox, function(target:DisplayObjectContainer):void
{
processChildren(target, function(target:DisplayObjectContainer):void
{
//this will be called on grandchildren
if (target is Button)
{
//do something
}
});
});
为了让它看起来不那么吓人,可以用普通函数替换匿名函数,但这个想法应该很清楚。
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