如何在BaseHTTPRequestHandler子类中停止BaseHTTPServer.serve_forever（）？

Question

我在一个单独的线程中运行我的 HTTPServer （使用无法停止线程的线程模块......）并且希望在主线程也关闭时停止提供请求。 / p>

Python文档声明 BaseHTTPServer.HTTPServer 是 SocketServer.TCPServer 的子类，它支持 shutdown 方法，但它缺失了在 HTTPServer 。

整个 BaseHTTPServer 模块的文档很少：（

Answer 1

我应该首先说“我可能不会自己这样做，但我过去”。 serve_forever（来自SocketServer.py）方法如下所示：

def serve_forever(self):
    """Handle one request at a time until doomsday."""
    while 1:
        self.handle_request()

你可以用替换（子类中）而>而self.should_be_running ，并从另一个线程修改该值。类似的东西：

def stop_serving_forever(self):
    """Stop handling requests"""
    self.should_be_running = 0
    # Make a fake request to the server, to really force it to stop.
    # Otherwise it will just stop on the next request.
    # (Exercise for the reader.)
    self.make_a_fake_request_to_myself()

编辑：我挖出了当时使用的实际代码：

class StoppableRPCServer(SimpleXMLRPCServer.SimpleXMLRPCServer):

    stopped = False
    allow_reuse_address = True

    def __init__(self, *args, **kw):
        SimpleXMLRPCServer.SimpleXMLRPCServer.__init__(self, *args, **kw)
        self.register_function(lambda: 'OK', 'ping')

    def serve_forever(self):
        while not self.stopped:
            self.handle_request()

    def force_stop(self):
        self.server_close()
        self.stopped = True
        self.create_dummy_request()

    def create_dummy_request(self):
        server = xmlrpclib.Server('http://%s:%s' % self.server_address)
        server.ping()

Answer 2

在我的python 2.6安装中，我可以在底层TCPServer上调用它 - 它仍然存在于 HTTPServer 中：

TCPServer.shutdown


>>> import BaseHTTPServer
>>> h=BaseHTTPServer.HTTPServer(('',5555), BaseHTTPServer.BaseHTTPRequestHandler)
>>> h.shutdown
<bound method HTTPServer.shutdown of <BaseHTTPServer.HTTPServer instance at 0x0100D800>>
>>> 

Answer 3

我认为您可以使用 [serverName] .socket.close（）

Answer 4

另一种方法，基于 http://docs.python.org/2 /library/basehttpserver.html#more-examples ，是：而不是serve_forever（），只要满足条件，就保持服务，服务器在每个请求之前和之后检查条件。例如：

import CGIHTTPServer
import BaseHTTPServer

KEEP_RUNNING = True

def keep_running():
    return KEEP_RUNNING

class Handler(CGIHTTPServer.CGIHTTPRequestHandler):
    cgi_directories = ["/cgi-bin"]

httpd = BaseHTTPServer.HTTPServer(("", 8000), Handler)

while keep_running():
    httpd.handle_request()

Answer 5

事件循环在SIGTERM， Ctrl + C 或调用 shutdown（）时结束。

必须在 server_forever（）之后调用 server_close（）来关闭侦听套接字。

import http.server

class StoppableHTTPServer(http.server.HTTPServer):
    def run(self):
        try:
            self.serve_forever()
        except KeyboardInterrupt:
            pass
        finally:
            # Clean-up server (close socket, etc.)
            self.server_close()

简单服务器可以通过用户操作停止（SIGTERM， Ctrl + C ，...）：

server = StoppableHTTPServer(("127.0.0.1", 8080),
                             http.server.BaseHTTPRequestHandler)
server.run()

服务器在线程中运行：

import threading

server = StoppableHTTPServer(("127.0.0.1", 8080),
                             http.server.BaseHTTPRequestHandler)

# Start processing requests
thread = threading.Thread(None, server.run)
thread.start()

# ... do things ...

# Shutdown server
server.shutdown()
thread.join()

Answer 6

在python 2.7中，调用shutdown（）可以正常工作，但前提是你通过serve_forever服务，因为它使用async select和一个轮询循环。使用handle_request（）运行你自己的循环具有讽刺意味的是排除了这个功能，因为它意味着一个愚蠢的阻塞调用。

来自SocketServer.py的BaseServer：

def serve_forever(self, poll_interval=0.5):
    """Handle one request at a time until shutdown.

    Polls for shutdown every poll_interval seconds. Ignores
    self.timeout. If you need to do periodic tasks, do them in
    another thread.
    """
    self.__is_shut_down.clear()
    try:
        while not self.__shutdown_request:
            # XXX: Consider using another file descriptor or
            # connecting to the socket to wake this up instead of
            # polling. Polling reduces our responsiveness to a
            # shutdown request and wastes cpu at all other times.
            r, w, e = select.select([self], [], [], poll_interval)
            if self in r:
                self._handle_request_noblock()
    finally:
        self.__shutdown_request = False
        self.__is_shut_down.set()

我的部分代码是从另一个线程执行阻塞关闭，使用事件等待完成：

class MockWebServerFixture(object):
    def start_webserver(self):
        """
        start the web server on a new thread
        """
        self._webserver_died = threading.Event()
        self._webserver_thread = threading.Thread(
                target=self._run_webserver_thread)
        self._webserver_thread.start()

    def _run_webserver_thread(self):
        self.webserver.serve_forever()
        self._webserver_died.set()

    def _kill_webserver(self):
        if not self._webserver_thread:
            return

        self.webserver.shutdown()

        # wait for thread to die for a bit, then give up raising an exception.
        if not self._webserver_died.wait(5):
            raise ValueError("couldn't kill webserver")

Answer 7

我成功使用此方法（Python 3）从Web应用程序本身（网页）停止服务器：

import http.server
import os
import re

class PatientHTTPRequestHandler(http.server.SimpleHTTPRequestHandler):
    stop_server = False
    base_directory = "/static/"
    # A file to use as an "server stopped user information" page.
    stop_command = "/control/stop.html"
    def send_head(self):
        self.path = os.path.normpath(self.path)
        if self.path == PatientHTTPRequestHandler.stop_command and self.address_string() == "127.0.0.1":
            # I wanted that only the local machine could stop the server.
            PatientHTTPRequestHandler.stop_server = True
            # Allow the stop page to be displayed.
            return http.server.SimpleHTTPRequestHandler.send_head(self)
        if self.path.startswith(PatientHTTPRequestHandler.base_directory):
            return http.server.SimpleHTTPRequestHandler.send_head(self)
        else:
            return self.send_error(404, "Not allowed", "The path you requested is forbidden.")

if __name__ == "__main__":
    httpd = http.server.HTTPServer(("127.0.0.1", 8080), PatientHTTPRequestHandler)
    # A timeout is needed for server to check periodically for KeyboardInterrupt
    httpd.timeout = 1
    while not PatientHTTPRequestHandler.stop_server:
        httpd.handle_request()

这样，通过基地址 http：// localhost：8080 / static / 提供的页面（例如 http：// localhost：8080 / static / styles / common.css ）将由默认处理程序提供，从服务器的计算机访问 http：// localhost：8080 / control / stop.html 将显示 stop.html 然后停止服务器，禁止任何其他选项。

Answer 8

我尝试了以上所有可能的解决方案，最终得到了“有时”的解决方案。问题 - 不知怎的，它并没有真正做到 - 所以我最终制作了一个对我来说一直都有效的肮脏解决方案：

如果以上都失败了，那么暴力破坏你的线程会使用类似的东西：

import subprocess
cmdkill = "kill $(ps aux|grep '<name of your thread> true'|grep -v 'grep'|awk '{print $2}') 2> /dev/null"
subprocess.Popen(cmdkill, stdout=subprocess.PIPE, shell=True)