如何从GMF编辑器中迭代EMF模型,而不会解析XML模型文件?
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10-10-2019 - |
题
我已经成功地创建了一个GMF编辑器,该编辑器根据我的EMF模型绘制模型。我想做的是通过模型的Eclasses迭代。可以通过我的插件代码在运行时实现这一点,而无需读取GMF Editor的XML文件创建?是否有EMF的API?
解决方案
当您从GenModel文件生成测试代码时,然后在xyz.test插件内部,我正在搜索这样的代码。它穿过模型的XMI文件
// Create a resource set to hold the resources.
//
ResourceSet resourceSet = new ResourceSetImpl();
// Register the appropriate resource factory to handle all file extensions.
//
resourceSet.getResourceFactoryRegistry().getExtensionToFactoryMap().put
(Resource.Factory.Registry.DEFAULT_EXTENSION,
new XMIResourceFactoryImpl());
// Register the package to ensure it is available during loading.
//
resourceSet.getPackageRegistry().put
(XYZmetamodelPackage.eNS_URI,
XYZmetamodelPackage.eINSTANCE);
// If there are no arguments, emit an appropriate usage message.
//
if (args.length == 0) {
System.out.println("Enter a list of file paths or URIs that have content like this:");
try {
Resource resource = resourceSet.createResource(URI.createURI("http:///My.metamodel"));
ModelObject root = atagmetamodelFactory.eINSTANCE.createModelObject();
resource.getContents().add(root);
resource.save(System.out, null);
}
catch (IOException exception) {
exception.printStackTrace();
}
}
else {
// Iterate over all the arguments.
//
for (int i = 0; i < args.length; ++i) {
// Construct the URI for the instance file.
// The argument is treated as a file path only if it denotes an existing file.
// Otherwise, it's directly treated as a URL.
//
File file = new File(args[i]);
URI uri = file.isFile() ? URI.createFileURI(file.getAbsolutePath()): URI.createURI(args[i]);
try {
// Demand load resource for this file.
//
Resource resource = resourceSet.getResource(uri, true);
System.out.println("Loaded " + uri);
// Validate the contents of the loaded resource.
//
for (EObject eObject : resource.getContents()) {
Diagnostic diagnostic = Diagnostician.INSTANCE.validate(eObject);
if (diagnostic.getSeverity() != Diagnostic.OK) {
printDiagnostic(diagnostic, "");
}
}
}
catch (RuntimeException exception) {
System.out.println("Problem loading " + uri);
exception.printStackTrace();
}
}
}
}
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