Simple but Impossible single MYSQL One to Many Query

Question

Staff Table

ID Name   Gender
1  John   Male
2  Adam   Male
3  Joella Female

Food Table

ID StaffID Name
1  1       Eggs
2  1       Bacon
3  1       Toast
4  2       Eggs
5  2       Bacon
6  3       Toast

I need the name of the MALE staff member who has consumed both eggs and toast.
The answer should be John, but everytime I used an AND clause it is zero results because it is looking at the same "row field". Using an OR returns the incorrect results.

I tried left join, standard join, and a few others.

SELECT field from table left join table2 on table.field=table2.field 
where field ='eggs' && field = 'toast' && gender = 'male'

The trick to this is I am trying to do this in a single query.

Answer 1

field cannot be eggs and toast at the same time, so join on the same table again

SELECT field from table left join table2 ON table.field = table2.field
left join table2 table22 ON table.field = table22.field
WHERE table2.field = 'eggs' AND table22.field = 'toast' && gender = 'male'

I'm also pretty sure that you don't want to join ON "field," but on some other column like the staffID.

Answer 2

Group by staff member and then filter the resulting groups for those that satisfy the desired criteria:

SELECT   Staff.Name
FROM     Staff JOIN Food ON Food.StaffID = Staff.ID
WHERE    Food.Name IN ('Eggs', 'Toast')
     AND Staff.Gender = 'Male'
GROUP BY Staff.ID
HAVING   COUNT(Food.ID) = 2

Answer 3

SELECT name, count(Food.id) AS foodcount
FROM Staff
LEFT JOIN Food ON Staff.id = Food.StaffID
WHERE Food.Name IN ('eggs', 'toast') AND gender = 'male'
GROUP BY Staff.id
HAVING foodcount = 2;

Answer 4

you can go with JOIN syntax, or with IN syntax

SELECT name from staf
where
ID in (select StaffId from food where Name='egg') and
ID in (select StaffId from food where Name='toast') and
gender = 'male'

Answer 5

select s.name from staff_table s join food_table f1 on f1.staff_id=s.id join food_table f2 on f2.staff_id=s.id where f1.name='Toast' and f2.name='Eggs' and s.gender='Male'