Considering this typedef:

case class Outer(someVal: Int) {
  case class Inner(someOtherVal: Int)
}

how do I construct an object of type Inner, (i.e. how do I write the valid scala syntax)?

I want the Inner to scoped to Outer to avoid name clashes with different instances of Outer in the same package.

有帮助吗?

解决方案

Inner is in scope of an outer instance. So, you can write something like that :

val res = new Outer(4)
val res2 = new res.Inner(2)

But, i don't think it's what you want. To avoid name clashes, you can use package, it is made for that.

edit :

You can also define Inner in companion object of Outer, like om-nom-nom said :

case class Outer(someVal : Int)
object Outer {
  case class Inner(otherVal : Int)
}

val res = Outer(5)
val in = Outer.Inner(6)
许可以下: CC-BY-SA归因
不隶属于 StackOverflow
scroll top