Oracle查询：获得具有大于阈值的不同名称

Question

我有一张桌子上有架构

EmpID,MachineID,Timestamp
    1,        A,01-Nov-13
    2,        A,02-Nov-13
    3,        C,03-Nov-13
    1,        B,02-Nov-13
    1,        C,04-Nov-13
    2,        B,03-Nov-13
    3,        A,02-Nov-13

所需的输出：

EmpID,MachineID
    1,        A
    1,        B
    1,        C
    2,        A
    2,        B
    3,        A
    3,        C

因此，基本上，我想找到在给定时间段内使用多台机器的EMP。

我正在使用的查询是

select EmpID,count(distinct(MachineID)) from table 
where Timestamp between '01-NOV-13' AND '07-NOV-13'
group by EmpID having count(distinct(MachineID)) > 1
order by count(distinct(MachineID)) desc;

这个查询是这样输出的

EmpID,count(distinct(MachineID))
    1,                        3
    2,                        2
    3,                        2   

任何人都可以帮助进行更改以获取我的问题上所述的输出。

Answer 1

一种可能的解决方案：

CREATE TABLE emp_mach (
  empid NUMBER,
  machineid VARCHAR2(1),
  timestamp_val DATE
);

INSERT INTO emp_mach VALUES (1,'A', DATE '2013-11-01');
INSERT INTO emp_mach VALUES (2,'A', DATE '2013-11-02');
INSERT INTO emp_mach VALUES (3,'C', DATE '2013-11-03');
INSERT INTO emp_mach VALUES (1,'B', DATE '2013-11-02');
INSERT INTO emp_mach VALUES (1,'C', DATE '2013-11-04');
INSERT INTO emp_mach VALUES (2,'B', DATE '2013-11-03');
INSERT INTO emp_mach VALUES (3,'A', DATE '2013-11-02');

COMMIT;

SELECT DISTINCT empid, machineid
  FROM emp_mach
WHERE empid IN (
  SELECT empid
    FROM emp_mach
  WHERE timestamp_val BETWEEN DATE '2013-11-01' AND DATE '2013-11-07'
  GROUP BY empid
  HAVING COUNT(DISTINCT machineid) > 1
)
ORDER BY empid, machineid;

（我更改了 timestamp 列到 timestamp_val)

输出：

     EMPID MACHINEID
---------- ---------
         1 A         
         1 B         
         1 C         
         2 A         
         2 B         
         3 A         
         3 C  

Answer 2

你做得最艰难。您的查询必须用于滤除结果：

SELECT t1.empid, t1.machineid
FROM
    table t1
WHERE
    EXIST (
        SELECT
            empid
        FROM table t2
        WHERE 
            timestamp BETWEEN '01-NOV-13' AND '07-NOV-13'
        AND t2.empid = t1.empid
        GROUP BY empid HAVING COUNT(distinct(machineid)) > 1
)
ORDER BY empid, machineid;

编辑：在Przemyslaw Kruglej之后发布几秒钟。我会在这里留在这里，因为它只是另一个选择（使用 EXIST 代替 IN)

Answer 3

   SELECT * FROM
        (SELECT DISTINCT(EmpID),COUNT(*) AS NumEMP
        from TableA
        WHERE Timestamp between '01-NOV-13' AND '07-NOV-13'
        group by EmpID 
        order by EmpID
        )
   WHERE NumEmp >= 1