我有一个按钮,可导致创建弹出窗口:

<ItemTemplate>
        <asp:Button ID="viewHoursButton" runat="server" Text="View Hours" OnClick="viewHoursButton_OnClick" />
        <ajaxToolkit:ModalPopupExtender ID="viewHoursPopup" runat="server"
                TargetControlID="viewHoursButton"
                PopupControlID="viewHoursPanel"
                CancelControlID="closeInfoPanelButton2"
                DropShadow="true">
                </ajaxToolkit:ModalPopupExtender>
    <asp:Panel ID="viewHoursPanel" runat="server" CssClass="infoPanel">
           //content of panel including gridview
    </asp:Panel>
</ItemTemplate>

弹出的面板带有一个GridView,当按下按钮时,SQL参数将传递。 :

protected void viewHoursButton_OnClick(object sender, EventArgs e)
{
    Button btn = sender as Button;
    GridViewRow row = btn.NamingContainer as GridViewRow;
    SqlDataSource6.SelectParameters["nonScrumStoryId"].DefaultValue = storyGridView.DataKeys[row.RowIndex].Values[0].ToString();
    var viewHoursGridView = storyGridView.FindControl("viewHoursGridView") as GridView;
    if (viewHoursGridView != null)
    {
        viewHoursGridView.DataBind();
    }
}

问题在于,GridView没有显示,因为服务器没有寄回。当您将按钮添加到ajaxtoolkit:modalPopupExtender时,寄回将被淘汰。我该如何找回它?

有帮助吗?

解决方案

您可以通过附加使用JavaScript强制寄回 __doPostBack 参加活动。

function doClick(sender, e) { 
__doPostBack(sender,e); 
} 

其他提示

嗨,我使用此代码JavaScript关闭弹出窗口和刷新父母webform

    Dim str_java As String = "<script language='javascript'>"
    str_java += (" window.onunload = refreshParent; ")
    str_java += (" function refreshParent() { ")
    str_java += (" window.self.location.reload(true); } ")
    str_java += (" window.close(); ")
    str_java += ("</script>")

    ScriptManager.RegisterStartupScript(Me, GetType(Page), "cerrarpagina", str_java, False)

这可以帮助您

许可以下: CC-BY-SA归因
不隶属于 StackOverflow
scroll top