Javascript：每个数组

Question

注意：没有jQuery
我怎么能这样做：

var array = new Array();
array[name] = "Tom";
array[age] = 15;
foreach(array as key=>value){
    alert(key + " = " + value);
}

Answer 1

首先，你应该把它叫做 obj 或 person 而不是 array ;数组是一系列相似的元素，而不是单个对象。

你可以这样做：

var person = new Object();
person['name'] = "Tom";
person['age'] = 15;
for (var key in person) {
    if(!person.hasOwnProperty(key)) continue;     //Skip base props like toString

    alert(key + " = " + person[key]);
}

您还可以使用属性初始化对象，如下所示：

person.name = "Tom";
person.age = 15;

您还可以使用 JavaScript对象文字语法：

var person = { name: "Tom", age: 15 };

Answer 2

这将在您的简单示例场景中起作用：

for (var key in array) {
  alert(key + " = " + array[key]);
}

对于一般用途，建议您进行测试以确保该物业没有'被嫁接到继承链中其他地方的对象上：

for (var key in array) {
  if (array.hasOwnProperty(key)) {
    alert(key + " = " + array[key]);
  }
}

Answer 3

使用javascript对象

var object = {};
object.name = "Tom";
object.age = 15;
for ( var i in object ) {
    console.log(i+' = '+ object[i]);
}

Answer 4

首先，你不需要一个数组，你想要一个对象。关于什么构成数组的PHP的想法坦率地说有点奇怪。

var stuff = {
    name: "Tom",
    age: 15
};

/* Note: you could also have done
var stuff = {};
stuff.name = "Tom";
stuff.age = 15;

// or

var stuff = {};
stuff["name"] = "Tom";
stuff["age"] = 15;

*/

for (var key in stuff) {
    alert(key + " = " + stuff[key];
}

Answer 5

key=0;while(key<array.length) {
    alert(key + " = " + array.item(key));
    key++;
}