我怎么能在nhibernate中查询持久化对象的属性的子属性?
-
08-07-2019 - |
题
我感到愚蠢。
public class Uber
{
public Foo Foo { get; set; }
public Bar Bar { get; set; }
}
public class Foo
{
public string Name { get; set; }
}
...
var ubercharged = session.CreateCriteria(typeof(Uber))
.Add(Expression.Eq("Foo.Name", "somename"))
.UniqueResult<Uber>();
return ubercharged;
这会抛出“无法解析属性”错误。
我做错了什么?我想查询具有属性Foo的Uber对象,该属性名称为“somename”。
使用流畅的nhibernate:
更新现实生活中的示例,存储库调用 public UserPersonalization GetUserPersonalization(string username)
{
ISession session = _sessionSource.GetSession();
var personuser = session.CreateCriteria(typeof(UserPersonalization))
.Add(Expression.Eq("User.Username", username))
.UniqueResult<UserPersonalization>();
return personuser;
}
类/映射:
public class User
{
public virtual Guid UserId { get; set; }
public virtual string Username { get; set; }
public virtual string Email { get; set; }
public virtual string PasswordHash { get; set; }
public virtual string PasswordSalt { get; set; }
public virtual bool IsLockedOut { get; set; }
public virtual bool IsApproved { get; set; }
}
public class Person
{
public virtual int PersonId { get; set; }
public virtual string Name { get; set; }
public virtual Company Company { get; set; }
}
public class UserPersonalization
{
public virtual int UserPersonalizationId { get; set; }
public virtual Person Person { get; set; }
public virtual User User { get; set; }
}
public class UserMap : ClassMap<User>
{
public UserMap()
{
Id(x => x.UserId).GeneratedBy.Guid().ColumnName("UserId");
Map(x => x.Username);
Map(x => x.PasswordHash);
Map(x => x.PasswordSalt);
Map(x => x.Email);
Map(x => x.IsApproved);
Map(x => x.IsLockedOut);
}
}
public class UserPersonalizationMap : ClassMap<UserPersonalization>
{
public UserPersonalizationMap()
{
WithTable("UserPersonalization");
Id(x => x.UserPersonalizationId).ColumnName("UserPersonalizationId");
References(x => x.Person).ColumnName("PersonId");
References(x => x.User).ColumnName("UserId");
}
}
public class PersonMap : ClassMap<Person>
{
public PersonMap()
{
Id(x => x.PersonId).ColumnName("PersonId");
Map(x => x.Name);
References(x => x.Company).ColumnName("CompanyId");
}
}
解决方案
试试这个:
var ubercharged = session.CreateCriteria(typeof(Uber))
.CreateCriteria("Foo")
.Add(Restrictions.Eq("Name", "somename"))
.UniqueResult<Uber>();
其他提示
您可以使用“ubercharged.AddOrder(Order.asc(&quot; Foo.Name”))语法进行排序吗?此语法应适用于NHib 2.01。如果没有,您的地图无法正常工作。
Stuart的回答应该对你有用。
不隶属于 StackOverflow