如何在NHIBERNATE中使用存储程序
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23-10-2019 - |
题
您好,我尝试使用NHIBERNATE中的存储过程,我发现了一些方法:
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
<sql-query name="CO_Visites_Treeview_Sel">
exec CO_Visites_Treeview_Sel :Idclient, :Idmagasin, :Autre, :Tous
</sql-query>
</hibernate-mapping>
如果我想使用我将使用的数据:
var query = session.GetNamedQuery("CO_Visites_Treeview_Sel");
query.SetString("Idclient", lstClients.SelectedValue.ToString());
query.SetInt32("Idmagasin", 36);
query.SetBoolean("Autre", false);
query.SetBoolean("Tous", true);
var results = query.List();
在这种情况下,我不会有智能的结果['colname'
我使用另一种方法:
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
<class name="NHibernate.DataAccess.Models.Visites_Treeview,NHibernate.DataAccess" lazy="true">
<id name="Idvisite" column="IDVISITE" type="string">
<generator class="assigned" />
</id>
<property column="NOMMAGASIN" name="Nommagasin" type="string" />
<property column="DATEVIS" name="Datevis" type="DateTime" />
<property column="INTERVENTION" name="Intervention" type="Boolean" />
<property column="IDFACTURE" name="Idfacture" type="string" />
<property column="STATUT" name="Statut" type="byte" />
<property column="NOFACTURE" name="Nofacture" type="int" />
<property column="NODEVIS" name="Nodevis" type="int" />
<property column="LIVRE" name="Livre" type="Boolean" />
<property column="NOCOMMANDE" name="Nocommande" type="int" />
<property column="COMPTABILISEE" name="Comptabilisee" type="Boolean" />
<property column="RECUP" name="Recup" type="Boolean" />
<property column="MASQUE" name="Masque" type="Boolean" />
</class>
<sql-query name="CO_Visites_Treeview_Sel">
<return alias="Visites_Treeview" class="NHibernate.DataAccess.Models.Visites_Treeview,NHibernate.DataAccess">
<return-property column="NOMMAGASIN" name="Nommagasin" />
<return-property column="IDVISITE" name="Idvisite" />
<return-property column="DATEVIS" name="Datevis" />
<return-property column="INTERVENTION" name="Intervention" />
<return-property column="IDFACTURE" name="Idfacture" />
<return-property column="STATUT" name="Statut" />
<return-property column="NOFACTURE" name="Nofacture" />
<return-property column="NODEVIS" name="Nodevis" />
<return-property column="LIVRE" name="Livre" />
<return-property column="NOCOMMANDE" name="Nocommande" />
<return-property column="COMPTABILISEE" name="Comptabilisee" />
<return-property column="RECUP" name="Recup" />
<return-property column="MASQUE" name="Masque" />
</return>
exec CO_Visites_Treeview_Sel :Idclient, :Idmagasin, :Autre, :Tous
</sql-query>
</hibernate-mapping>
我创建了一个Bean类。在这种情况下,结果将具有强烈键入的对象,但我有一些连贯性问题。但是我没有真正的标识符,因此,如果有两个idvisite,则第二个将被忽略。我尝试创建一个复合键,但它不起作用。
<composite-id>
<key-property name="Idvisite" column="IDVISITE" type="string" />
<key-property name="Idfacture" column="IDFACTURE" type="string" />
</composite-id>
而且我有一个错误:
could not execute query
[ exec CO_Visites_Treeview_Sel @p0, @p1, @p2, @p3 ]
Name:Idclient - Value:036000004130 Name:Idmagasin - Value:36 Name:Autre - Value:False Name:Tous - Value:True
[SQL: exec CO_Visites_Treeview_Sel @p0, @p1, @p2, @p3]
有人可以告诉我怎么做吗?
问候
解决方案
尝试一下,您的映射: -
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2">
<sql-query name="CO_Visites_Treeview_Sel">
exec CO_Visites_Treeview_Sel :Idclient, :Idmagasin, :Autre, :Tous
</sql-query>
</hibernate-mapping>
使用SetResultTransFormer ...
var results = Session
.GetNamedQuery("CO_Visites_Treeview_Sel")
.SetString("Idclient", lstClients.SelectedValue.ToString())
.SetInt32("Idmagasin", 36)
.SetBoolean("Autre", false)
.SetBoolean("Tous", true)
.SetResultTransformer(new AliasToBeanResultTransformer(typeof(YOURCLASS)));
return results.List<YOURCLASS>();
和您的班级是: -
public class YOURCLASS
{
public virtual int ColA { get; set; }
public virtual string COLB { get; set; }
public virtual int COLC { get; set; }
// etc..
}
Hth
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