The second parameter to strtotime defaults to current time. So the following should produce desired result:
$nextdate = date('Ynd', strtotime('+1 day'));
// Today is 2014117, Tomorrow is 2014118
题
I'm getting the output of:
Warning: strtotime() expects parameter 2 to be long, string given in C:\xampp\htdocs\MindWeather\Assimilation\foreca_hourly.php on line 17
Today is 2014117, Tomorrow is 1970101
My code is:
$TodayIs = date('Ynd');
$nextdate = date('Ynd', strtotime($TodayIs,'+ 1 day'));
echo "<br><br> Today is $TodayIs, Tomorrow is $nextdate<br><br>";
I really don't expect to get a 1970-answer. It's supposed to display "Today is 2014117, Tomorrow is 2014118" instead of "Today is 2014117, Tomorrow is 1970101"
解决方案
The second parameter to strtotime defaults to current time. So the following should produce desired result:
$nextdate = date('Ynd', strtotime('+1 day'));
// Today is 2014117, Tomorrow is 2014118
其他提示
Why don't you make use of a DateTime
Class ?
<?php
$date = new DateTime();
echo "Today is ".$date->format('Y/m/d');
$date->add(new DateInterval('P1D'));
echo "<br>Tomorrow is ".$date->format('Y/m/d');
OUTPUT :
Today is 2014/01/17
Tomorrow is 2014/01/18
Try like this:
$TodayIs = date('Ynd');
$nextdate = date('Ynd', strtotime('+ 1 day'));
echo "<br><br> Today is $TodayIs, Tomorrow is $nextdate<br><br>";
PHPfiddle link: http://phpfiddle.org/lite/code/bnf-scw
Try this:
$date = '2013-10-15';
$new_time = strtotime('+1 day', strtotime($date));
echo date('d-m-Y', $new_time); //displays 2013-10-16