我正在尝试获取本地PC的IP地址,并且我的其他PC中的一个获得了v4地址,但是在这个代码上:

Dns.GetHostEntry(Dns.GetHostName).AddressList(0).ToString()

返回我猜的IPv6地址:

fe80::9c09:e2e:4736:4c62%11

如何获取IPv4地址?

有帮助吗?

解决方案

免责声明 - 我没有安装IPv6,并且可能有更好的方法来执行此操作,但以下内容会返回:

Dns.GetHostEntry(Dns.GetHostName()).AddressList
    .Where(a => !a.IsIPv6LinkLocal && !a.IsIPv6Multicast && !a.IsIPv6SiteLocal)
    .First()
    .ToString();

编辑 - 没有注意到你在VB中提问,所以我尝试将其翻译成:

Dim s As String = Dns.GetHostEntry(Dns.GetHostName()).AddressList _
    .Where(Function(a As IPAddress) Not a.IsIPv6LinkLocal AndAlso Not a.IsIPv6Multicast AndAlso Not a.IsIPv6SiteLocal) _
    .First() _
    .ToString()

这可能会爆炸,所以不要将其视为生产代码。

其他提示

这是我在不使用外部服务的情况下获取可路由IPv4 IP的解决方案:

  Function GetLocalIP() As String
    Dim IPList As System.Net.IPHostEntry = System.Net.Dns.GetHostEntry(System.Net.Dns.GetHostName)

    For Each IPaddress In IPList.AddressList
      'Only return IPv4 routable IPs
      If (IPaddress.AddressFamily = Sockets.AddressFamily.InterNetwork) AndAlso (Not IsPrivateIP(IPaddress.ToString)) Then
        Return IPaddress.ToString
      End If
    Next
    Return ""
  End Function

  Function IsPrivateIP(ByVal CheckIP As String) As Boolean
    Dim Quad1, Quad2 As Integer

    Quad1 = CInt(CheckIP.Substring(0, CheckIP.IndexOf(".")))
    Quad2 = CInt(CheckIP.Substring(CheckIP.IndexOf(".") + 1).Substring(0, CheckIP.IndexOf(".")))
    Select Case Quad1
      Case 10
        Return True
      Case 172
        If Quad2 >= 16 And Quad2 <= 31 Then Return True
      Case 192
        If Quad2 = 168 Then Return True
    End Select
    Return False
  End Function

请注意,我的代码也验证范围是可路由的(IsPrivateIP)。如果您正在寻找其他内容,可以删除或修改该部分。

我认为你应该使用它:

 Dim tmpHostName As String = System.Net.Dns.GetHostName()
 myIPaddress = System.Net.Dns.GetHostByName(tmpHostName).AddressList(0).ToString()

GetHostByName已过时,但这是获取IPv4的方法。为什么?因为getbyhostname函数是在IPv6之前创建的,所以函数只获得IPv4连接,而不是fe80::9c09:e2e:4736:4c62%11

这个小功能可以显示计算机上的所有IP地址:

Public Function getOwnIp() As String
        Dim hostIP As IPHostEntry = Dns.GetHostEntry(Dns.GetHostName())
        Dim position As Integer = 0
        Dim ip As String = Nothing
        While ipList < hostIP.AddressList.Length
            ip += hostIP.AddressList(position).ToString & vbCrLf
            position += 1
        End While`enter code here`
        Return ip
    End Function

我一直在寻找这个问题的答案,我找不到适合我需要的答案。我设法在网上试验各种答案,直到我想出这个(效果很好!)。只是想我会分享,因为这篇文章是谷歌的最佳结果。

    ''''Routine to fetch IPv4 Network addresses for all local network interfaces.
    Dim adapters As NetworkInterface() = NetworkInterface.GetAllNetworkInterfaces()
    Dim adapter As NetworkInterface
        For Each adapter In adapters
            Dim properties As IPInterfaceProperties = adapter.GetIPProperties()
            If properties.UnicastAddresses.Count > 0 Then
                For Each unicastadress As UnicastIPAddressInformation In properties.UnicastAddresses
                    Dim ip As IPAddress = unicastadress.Address
                    If ip.AddressFamily = AddressFamily.InterNetwork Then
                        ComboBox1.Items.Add(ip.ToString)
                    End If
                Next unicastadress
            End If
        Next adapter

首先需要将系统命名空间导入到您的应用程序中,然后创建 System.Net.NetworkInformation.IPAddressInformation 的实例并将其用作

实施例

  Imports system.data.sqlclient
    imports system

Public class Form1
   Dim IPAdd As System.Net.NetworkInformation.IPAddressInformation

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

 MsgBox("My IP Address is " & IPAdd.Address.ToString)
    End Sub
End Class
 Dim localIp As IPHostEntry = Dns.GetHostEntry(Dns.GetHostName())
 txtLocal.Text = localIp.AddressList(1).ToString

请注意,我将(0)索引更改为(1)

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