题
我已经开发了以下类来检索XML文档的节点列表:
public class XMLDownloader {
public static NodeList getNodeList(){
String url = "http://localhost/xml/example.xml";
DefaultHttpClient client = new DefaultHttpClient();
HttpGet method = new HttpGet(url);
HttpResponse res = null;
NodeList result = null;
try {
res = client.execute(method);
} catch (ClientProtocolException e1) {
e1.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
}
try{
InputStream is = res.getEntity().getContent();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.parse(is);
doc.getDocumentElement().normalize();
result = doc.getElementsByTagName("client");
is.close();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
return result;
}
}
但是此方法返回 null
. 。有任何想法吗?
XML文件:
<status>
<client type="s" name="test1" protocol="1000">
</client>
<client type="r" name="test2" protocol="2000">
</client>
<client type="r" name="test3" protocol="3000">
</client>
<client type="h" name="test4" protocol="4000">
</client>
<client type="c" name="test5" protocol="5000">
</client>
</status>
解决方案
该问题中发布的代码实际上对我有用,没有任何错误。我得到了一个结节,其中包含预期的5个元素。我在运行2.2的模拟器上尝试了它。
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