echo $a | awk '{print $1}' FS=[0-9]
Cut using delimiter as number for a string in shell
题
a="abc-ABC-3.2-def"
For the above mentioned variable, I need to cut so that i get all the string before occurrence of number.
Output expected after cut is,
abc-ABC-
The number can be anything, Please help.
解决方案
其他提示
Using bash strings:
echo ${a%%[0-9]*}
%% means greedy pattern matching from the right, we match any digit (0-9) followed by some text (or nothing).
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