Try:
<dg:segment xsi:type="dg:SegmentEauType">
{
for $attr_name in fme:get-list-attribute("_att{}._attr_name")
return element { $attr_name } { 'value' }
}
</dg:segment>
题
Does someone guru xquery?
I have a XQuery FLWOR expression:
<dg:segment xsi:type="dg:SegmentEauType">
{
for $attr_name in fme:get-list-attribute("_att{}._attr_name")
return <attribut name="{$attr_name}">value</attribut>
}
</dg:segment>
that produce
<dg:segment xsi:type="dg:SegmentEauType">
<attribut name="DIAMETREM_R">value</attribut>
<attribut name="PROVENANCEDONNEE_R">value</attribut>
<!-- etc... -->
</dg:segment>
How can I get that XML node?
<dg:segment xsi:type="dg:SegmentEauType">
<DIAMETREM_R>value<DIAMETREM_R>
<PROVENANCEDONNEE_R>value<PROVENANCEDONNEE_R>
<!-- etc... -->
</dg:segment>
I've tried, but I got an error.
for $attr_name in fme:get-list-attribute("_att{}._attr_name")
return <{$attr_name}>value</{$attr_name}>
Don't matter about fme:get-list-attribute function...
Many Tx!
解决方案
Try:
<dg:segment xsi:type="dg:SegmentEauType">
{
for $attr_name in fme:get-list-attribute("_att{}._attr_name")
return element { $attr_name } { 'value' }
}
</dg:segment>