滑动手势到滑动uiviews
-
26-10-2019 - |
题
我想做滑动手势以滑动 UIView
连续获取数据。考虑每个单词 UIView
. 。我将数据存储在数组中,并以标签印刷 UIView
在过渡时。但是,当我尝试滑动后,显示所有数据程序都停止工作。我的项目没有显示错误。请帮助我。
这是我的数组:
addArray = [[NSMutableArray alloc]initWithCapacity:4];
[addArray insertObject:@"10" atIndex:0];
[addArray insertObject:@"20" atIndex:1];
[addArray insertObject:@"30" atIndex:2];
[addArray insertObject:@"40" atIndex:3];
flippedArray = [[NSMutableArray alloc] initWithCapacity:4];
[flippedArray insertObject:@"100" atIndex:0];
[flippedArray insertObject:@"200" atIndex:1];
[flippedArray insertObject:@"300" atIndex:2];
[flippedArray insertObject:@"400" atIndex:3];
这是我的手势识别器编码:
-(void)swipegesture:(UISwipeGestureRecognizer *)recognizer{
CGPoint location = [recognizer locationInView:additionalView];
if (recognizer.direction==UISwipeGestureRecognizerDirectionLeft)
{
if (increment<[addArray count])
{
NSLog(@"%d",[addArray count]);
increment++;
if(increment==[addArray count])
{
NSLog(@"Fail");
//[recognizer requireGestureRecognizerToFail:swipeGesture];
[recognizer setEnabled:NO];
}
else
{
additionalLabel.text=[[NSString alloc] initWithFormat:@"%@",
[addArray objectAtIndex:increment]];
flippedLabel.text = [[NSString alloc] initWithFormat:@"%@",
[flippedArray objectAtIndex:increment]];
NSLog(@"increment %d",increment);
[UIView animateWithDuration:0.55 animations:^{
[UIView setAnimationDelay:0.2];
}];
CATransition *animation = [CATransition animation];
[animation setType:kCATransitionPush];
[animation setSubtype:kCATransitionFromRight];
[animation setTimingFunction:[CAMediaTimingFunction
functionWithName:kCAMediaTimingFunctionDefault]];
[animation setSpeed:0.4];
[[additionalView layer] addAnimation:animation forKey:nil];
}
}
}
else if(recognizer.direction==UISwipeGestureRecognizerDirectionRight)
{
if (increment>=0 && increment<[addArray count])
{
increment--;
if(increment>[addArray count])
{
additionalLabel.text=[[NSString alloc]initWithFormat:@"%@",
[addArray objectAtIndex:increment]];
flippedLabel.text=[[NSString alloc]initWithFormat:@"%@",
[flippedArray objectAtIndex:increment]];
NSLog(@"Decrement %d",increment);
[UIView animateWithDuration:0.55 animations:^{
[UIView setAnimationDelay:0.2];
}];
CATransition *animation = [CATransition animation];
[animation setType:kCATransitionPush];
[animation setSubtype:kCATransitionFromLeft];
[animation setTimingFunction:[CAMediaTimingFunction
functionWithName:kCAMediaTimingFunctionDefault]];
[animation setSpeed:0.4];
[[additionalView layer] addAnimation:animation forKey:nil];
}
}
}
}
有一个问题,而仅增量。我有 NSLog
打印为失败。但是如果达到价值为 [addArray count]
.
解决方案
我建议在有效性检查之前递增或减少索引值(您命名为增量),如果没有有效的话,将您的操作反转为其他。像这样:
if (recognizer.direction==UISwipeGestureRecognizerDirectionLeft)
{
increment++;
if (increment<[addArray count])
{
// Your code
}
else
{
increment--; // The increment would pass the range of the array, set it back.
}
}
同样是另一个方向。
编辑:要澄清,最初的问题是您检查以确保索引有效,但是,通过在检查后递增您最终使其无效。使用您的示例,当增量为3(数组的最高索引)时,它实际上比数组计数少,即4.您将索引递增到4,或者在范围内,或者在您的中情况,属于IF语句(使用该建议将不再需要)并记录您的失败。
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