define var today and yesterday [duplicate]

题

I have

$today = date("Y-m-d");

and I like to define also $yesterday

I tried to do

$yesterday=($today-1)

But it doesn't work

解决方案

Just try with:

$yesterday = date('Y-m-d', strtotime('yesterday'));

其他提示

You could use something like:

date("F j, Y", time() - 60 * 60 * 24);

You can also use DateTime:

$date = new DateTime('');
$date->modify('-1 day');
echo $date->format('Y-m-d') . "\n";

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