Suppose I have method:

void foo(const std::string& s);

Can I create boost::function:

boost::function<void(const std::string&)> f = boost::bind(foo, temp);

where temp is char* that is deleted before f is called.

有帮助吗?

解决方案

Yes. Bind cannot know that the char* can be held in a string, or that it is being passed to a string. To circumvent this, use:

boost::bind(foo, std::string(temp));

So that your temp is copied into the binder as a string.

其他提示

And this is compiling for you? It should be

boost::function<void()> f = boost::bind(foo, std::string(temp));
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