#include <stdint.h>
#include <inttypes.h>
...
char *buffer="dddd:0000:0000:0000:0000:0000:0000:cccc";
uint8_t ipadress[16];
sscanf(buffer,
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ":"
"%2" SCNx8 "%2" SCNx8 ,
&ipadress[0],&ipadress[1],
&ipadress[2],&ipadress[3],
&ipadress[4],&ipadress[5],
&ipadress[6],&ipadress[7],
&ipadress[8],&ipadress[9],
&ipadress[10],&ipadress[11],
&ipadress[12],&ipadress[13],
&ipadress[14],&ipadress[15]);
converting char* to array of uint8_t (c)
题
I can make function calls and receive an array of strings that represents ipv6 adress. it looks something like this
char* buffer=resolver_getstring(config, INI_BOOT_MESHINTFIPADDRESS);
if i printed buffer i will gate the ipv6 adress in string form:
dddd:0000:0000:0000:0000:0000:0000:cccc
however, the way how ipv6 address is represented in my project is with 16 hexadecimal number by using uint8_t datatype as follows
uint8_t ipadress[16]
now my problem is how can i cast (or copy the memory of buffer) to uint8_t[16]
what i would like to get is
ipadress[0]=dd // hexadecimal number
ipaddress[1]=dd
....
ipaddress[15]=cc
is there anyway i could do ? Regards,
解决方案
其他提示
You'll need to look into strtok()
(to break the string into pieces at the colon char), strtol()
(to convert the pieces from hexadecimal form into binary) and some bit shifting and shuffling (to break the resulting 16 bit numbers into two separate bytes).
不隶属于 StackOverflow