我一直在问这个说法从PL / SQL转换到SQL Server:

UPDATE pdi_nb_process_complete pdi_end1
SET    (pdi_end1.adp_issue_date_time, pdi_end1.adp_print_date_time) = 
(SELECT DISTINCT pdi_end1.completion_date + 2
                ,pdi_end1.completion_date
 FROM   cl100 cl
 WHERE  cl.polref = pdi_end1.policy_reference
 AND    cl.doctyp = 'PSP')
WHERE  pdi_end1.adp_print_date_time IS NULL

一个直复制/粘贴不工作 - 你得到一个编译错误。我已设法最接近是这样的:

UPDATE pdi_end1
SET    pdi_end1.adp_issue_date_time = pdi_end1.completion_date + 2,
       pdi_end1.adp_print_date_time = pdi_end1.completion_date
from pdi_nb_process pdi_end1
INNER JOIN cl100 cl ON  cl.polref = pdi_end1.policy_reference
     AND cl.doctyp = 'PSP'
WHERE  pdi_end1.adp_print_date_time IS NULL

但是,这给我留下很短的 DISTINCT的。有没有人有什么建议吗?

您可以假设Oracle和SQL Server数据库具有相同的表和字段。

由于

有帮助吗?

解决方案

我会移动 AND cl.doctyp = 'PSP'的条件的WHERE,因为它不是一个连接条件。

尝试这样:

UPDATE pdi_end1
    SET pdi_end1.adp_issue_date_time=pdi_end1.completion_date + 2
        ,pdi_end1.adp_print_date_time)=pdi_end1.completion_date
    FROM pdi_nb_process_complete pdi_endl
        INNER JOIN cl100               cl ON cl.polref=pdi_end1.policy_reference
    WHERE pdi_end1.adp_print_date_time IS NULL
        AND cl.doctyp='PSP' 

我就不会担心了DISTINCT,SQL Server将只更新行一次,看到这样的例子:

SET NOCOUNT ON
DECLARE @Test table (RowID int, RowValue int, OtherRowValue int)
INSERT INTO @Test VALUES ( 1, 1, 10)
INSERT INTO @Test VALUES ( 2, 2, 20)
INSERT INTO @Test VALUES ( 3, 3, 30)
INSERT INTO @Test VALUES ( 4, 4, 40)
INSERT INTO @Test VALUES ( 5, 5, 50)
INSERT INTO @Test VALUES ( 6, 6, 60)
INSERT INTO @Test VALUES ( 7, 7, 70)
INSERT INTO @Test VALUES ( 8, 8, 80)
INSERT INTO @Test VALUES ( 9, 9, 90)
INSERT INTO @Test VALUES (10,10,100)

DECLARE @TestJoin table (RowID int, RowValue int)
INSERT INTO @TestJoin VALUES (1,10)
INSERT INTO @TestJoin VALUES (1,10)
INSERT INTO @TestJoin VALUES (1,10)
INSERT INTO @TestJoin VALUES (2,20)
INSERT INTO @TestJoin VALUES (2,20)
INSERT INTO @TestJoin VALUES (2,20)
INSERT INTO @TestJoin VALUES (2,20)
INSERT INTO @TestJoin VALUES (2,20)
INSERT INTO @TestJoin VALUES (3,30)
INSERT INTO @TestJoin VALUES (3,30)
SET NOCOUNT OFF

SELECT ---------------------------returns 5 rows, DISTINCT would only return 1
    t.OtherRowValue+2
    FROM @Test                t
        INNER JOIN @TestJoin  j ON t.RowID=j.RowID
    WHERE t.OtherRowValue=20
        AND j.RowValue=20

UPDATE t--------------------------updates only 1 row
    SET t.RowValue=t.OtherRowValue+2
    FROM @Test                t
        INNER JOIN @TestJoin  j ON t.RowID=j.RowID
    WHERE t.OtherRowValue=20
        AND j.RowValue=20

输出:

-----------
22
22
22
22
22

(5 row(s) affected)

(1 row(s) affected)

在SELECT返回5行,然而,当同样的选择被放入UPDATE,只有1行受到影响。

其他提示

您可以改变内连接到一个子查询:

inner join (
    select distinct policy_reference
    from cl100
    where doctyp = 'PSP'
) cl on cl.polref = pdi_end1.policy_reference

或者,也许更加可读,取下内加入共并用WHERE语句替换:

WHERE  pdi_end1.adp_print_date_time IS NULL
AND EXISTS (
    select * 
    from cl100 cl
    where cl.polref = pdi_end1.policy_reference
    and cl.doctyp = 'PSP'
)
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