Try:
tail -f /some/file.log | awk ' $2>10 {if (!($1 in a)) print $1; a[$1]=1; system("")}' > /some/filteredfile.log
题
Edit: Instead of tossing out the duplicate data I want it to "overwrite" the duplicate data, meaning leave the data but update the timestamp
Problem 1:
I have a command line as follows,
tail -f /some/file.log | awk '$2>10 (if (!($1 in a)) print $1, strftime("%Y-%m-%d %H:%M:%S"); a[$1]=1 ;system("")}' > /some/filteredfile.log
However, I would like the output from this to only add the text to file if it isn't already there (in the 1st column), and if it is there, update the timestamp (in the second column)
解决方案
Try:
tail -f /some/file.log | awk ' $2>10 {if (!($1 in a)) print $1; a[$1]=1; system("")}' > /some/filteredfile.log
其他提示
One problem two part may be:
tail -f file.txt | awk -v date="$(date +"%Y-%m-%d-%h%m%s")" '$2>10 {print date, $1; system("")} ' > output.log
It should solve your 2nd part, working for me.