Hibernate的超脱查询作为条件查询的一部分

Question

Java的专家可以请你帮我写分离查询作为标准查询下面的SQL语句的一部分。

select A.*
FROM AETABLE A
where not exists
(
    select entryid
    FROM AETABLE B
    where B.classpk = A.classpk
    and B.userid = A.userid
    and B.modifiedDate > A.modifiedDate
)
and userid = 10146

Answer 1

您需要写一个相关子查询。假设属性/类名匹配列/上面表名：

DetachedCriteria subquery = DetachedCriteria.forClass(AETable.class, "b")
 .add(Property.forName("b.classpk").eqProperty("a.classpk"))
 .add(Property.forName("b.userid").eqProperty("a.userid"))
 .add(Property.forName("b.modifiedDate").gtProperty("a.modifiedDate"));

Criteria criteria = session.createCriteria(AETable.class, "a")
 .add(Property.forName("userid").eq(new Integer(10146)))
 .add(Subqueries.notExists(subquery);

Answer 2

仅有一个除上述查询。如果是的EntryID不是主键，那么你就需要添加投影。

DetachedCriteria subquery = DetachedCriteria.forClass(AETable.class, "b")
 .add(Property.forName("b.classpk").eqProperty("a.classpk"))
 .add(Property.forName("b.userid").eqProperty("a.userid"))
 .add(Property.forName("b.modifiedDate").gtProperty("a.modifiedDate"))
 .add(setProjection(Projections.property("entryId"));  // Additional projection property

Criteria criteria = session.createCriteria(AETable.class, "a")
 .add(Property.forName("userid").eq(new Integer(10146)))
 .add(Subqueries.notExists(subquery);