What is happening to this lambda ? could someone explain

Question

proc_obj = -> proto { print proto; puts("World")}

puts proc_obj["Hi"]

puts proc_obj.call("Hello") #Is this is the same as above

please refer me to some link to demystify this ...

Answer 1

What is happening to that lambda is that you're calling its [] method, which causes the lambda to be executed with the argument "Hi". And yes, calling call is the same as calling [].

Answer 2

http://www.ruby-doc.org/core-1.9.3/Proc.html#method-i-5B-5D