tic-tac-toe和||

Question

嗨，我17岁，试图自学C ++。对于我的第一个项目之一，我试图编写一款TIC-TAC-TOE游戏并与AI进行玩。所以代码我遇到麻烦了

main() {

    char player, computer;

    while (player != 'x' || player != 'o' )
    {
        cout << "do you want to be x or o?";
        cin >> player;
    };

    if (player == 'x' ) computer == 'o';
    else computer == 'x';

    cout << "player is: " << player << endl <<  "computer is: " << computer ;
    cout << computer;
};

我收到消息“您想成为X或O？”，但是然后输入X或O，它不断重复相同的问题。我认为这与时循环有关。任何帮助都将受到赞赏。

Answer 1

您的循环终端条件是错误的，直到您询问一次之前，您不应该检查。

do {
    cout << "do you want to be x or o?";
    cin >> player;
} while (player != 'x' && player != 'o');

Answer 2

char player, computer;

while (player != 'x' || player != 'o' ) {

首先， player 没有初始化任何东西，因此包含随机垃圾。您不应该从中读书。至少将其初始化为一些已知值。

其次，您的病情永远是正确的。假设 player 是 'x'. 。满足条件 player != 'o'.

你可能的意思是：

while (player != 'x' && player != 'o') {

Answer 3

您的问题是条件。我认为你的意思是 while (player != 'x' && player != 'o'), ，即何时 player 既不是X也不是O。

Answer 4

while ( (player == 'x' || player == 'o') == false )

Answer 5

    char player = ' '; // always init variables
    while (player != 'x' && player != 'o' ) //exit if false, when player == x or == o
    {
        cout << "do you want to be x or o?";
        cin >> player;
    };