I dont know why i'm having so much issues with parsing this simple json:

{"status":0,"result":{"success":false,"message":"Error"}}

How would I get the success and message String?

    try {
        river = response.getJSONArray("result");

        // looping through All Contacts
        for(int i = 0; i < river.length(); i++){
            JSONObject c = river.getJSONObject(i);

            if (c.has("message")) {
                message = c.getString("message");
                System.out.println("object_guid:"+message); }

            if (c.has("success")) {
                success = c.getString("success");
                System.out.println("subtype:"+success); }

        }

    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
有帮助吗?

解决方案

Replace

river = response.getJSONArray("result");                                                                                

with

river = response.getJSONObject("result");          

The result tag is a JSONObject and not a JSONArray

其他提示

Your result is not jsonarray, its an object.

{"status":0,"result":{"success":false,"message":"Error"}}

JSONObject river = response.getJSONObject("result"); 
String success = river.getString("success"); 
String message = river.getString("message"); 

In your response your are not getting JSONArray. It contains JSONObjects only. So you need to get the JSONObject not JSONArray.

Try out as below:

                 river = response.getJSONObject("result");                                                                                
                         if (river.has("message")) {
                                  message = river.getString("message");                   
                                  System.out.println("object_guid:"+message); }

                           if (river.has("success")) {
                                  success = river.getString("success");                   
                                 System.out.println("subtype:"+success); }
                            }
许可以下: CC-BY-SA归因
不隶属于 StackOverflow
scroll top