You're passing the result of the function rather than the function itself. You can use a lambda like so:
var foundItems = GetObject<List<string>>(key,
name => GetCultures<List<string>>(sitename));
You also have this line:
foundItems = f as T;
Here you're trying to cast the function itself to its return type, which won't work. Instead you could do:
foundItems = f(name);
But now your problem is that you'd have to pass the name into GetObject
, because otherwise it won't be accessible where it's needed. The reason for this is there's a mismatch between MyFunction
, which takes a string
, and what you actually want, which is a function that can be evaluated within GetObject
without needing the name parameter to be passed in.
So what you should really do is change your delegate to:
public delegate T MyFunction<T>();
Or alternatively get rid of the delegate altogether and have the f
parameter be a Func<T>
.
With either of these options, you can pass in the lamba with no parameter required:
var foundItems = GetObject<List<string>>(key,
() => GetCultures<List<string>>(sitename));
And evaluate it like:
foundItems = f();
Note that it's a bit roundabout to create a lambda to pass it into another method just to then evaluate it, rather than just passing the result in directly. So unless there's some reason that you need to do this in some cases, you might instead want to change the f
parameter to take a type T
instead. In this case I suspect you're doing it to lazily evaluate the function so that you don't have to evaluate if the result is already cached. That would probably be a valid reason, assuming you're not optimizing for performance prematurely.