为什么Unity的RegisterInstance <...>事业团结返回多个实例？

Question

统一的文档，其登记一个实例RegisterInstance <>方法的说，使得的返回的特定实例每次解决<>被称为即可。

然而，下面这个例子中示出了每个时间解决<>被调用时，的返回的类型的新实例

这是为什么？

using System;
using System.Windows;
using Microsoft.Practices.Unity;

namespace TestUnity34
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();

            Validator validator1 = new Validator();
            IUnityContainer container = new UnityContainer();
            container.RegisterInstance<IValidator>(validator1);

            Validator validatorCopied = validator1;
            Console.WriteLine(validator1.GetHashCode()); //14421545
            Console.WriteLine(validatorCopied.GetHashCode()); //14421545

            Validator validator2 = container.Resolve<Validator>();
            Console.WriteLine(validator2.GetHashCode()); //35567111

            Validator validator3 = container.Resolve<Validator>();
            Console.WriteLine(validator3.GetHashCode()); //65066874
        }
    }

    interface IValidator
    {
        void Validate();
        string GetStatus();
    }

    public class Validator : IValidator
    {
        public void Validate() { }

        public string GetStatus() { return "test"; }
    }
}

Answer 1

您已经配置了IValidator您的容器，这样你将不得不使用IValidator而不是验证解决：

Validator validator1 = new Validator(); 
IUnityContainer container = new UnityContainer(); 
container.RegisterInstance<IValidator>(validator1); 
Validator validatorCopied = validator1; 
Console.WriteLine(validator1.GetHashCode());
Console.WriteLine(validatorCopied.GetHashCode());
IValidator validator2 = container.Resolve<IValidator>();            
Console.WriteLine(validator2.GetHashCode());             
IValidator validator3 = container.Resolve<IValidator>();            
Console.WriteLine(validator3.GetHashCode()); 

另外，你可以保持您的注册使用验证但你必须使用验证，以及解决：

Validator validator1 = new Validator();
IUnityContainer container = new UnityContainer();
container.RegisterInstance<Validator>(validator1);
Validator validatorCopied = validator1;
Console.WriteLine(validator1.GetHashCode());
Console.WriteLine(validatorCopied.GetHashCode());
Validator validator2 = container.Resolve<Validator>();
Console.WriteLine(validator2.GetHashCode());
Validator validator3 = container.Resolve<Validator>();
Console.WriteLine(validator3.GetHashCode());

Answer 2

我觉得如果你有IValidator称为解析作为类型参数，因为你希望它会工作：

...
var validator2 = container.Resolve<IValidator>();
...