题
我有一个看似简单的烦人的SQL语句,但它看起来awfull。 我想要让某个用户在结果集的第一行,如果用户emailaddress可以在公司表的SQL返回与有序用户数据结果集。
我有这样的SQL返回我想要什么,但我认为它看起来可怕的:
select 1 as o, *
from Users u
where companyid = 1
and email = (select email from companies where id=1)
union
select 2 as o, *
from Users u
where companyid = 1
and email <> (select email from companies where id=1)
order by o
和的方式,从用户表中EMAILADDRESS可以在许多企业因此不能是在EMAILADDRESS联接: - (
你有什么想法如何改善这种说法?
林使用Microsoft SQL Server 2000。
编辑: 即时通讯使用这一个:
select *, case when u.email=(select email from companies where Id=1) then 1 else 2 end AS SortMeFirst
from Users u
where u.companyId=1
order by SortMeFirst
其方式比我更优雅。感谢理查德升!
解决方案
您可以做这样的事情..
select CASE
WHEN exists (select email from companies c where c.Id = u.ID and c.Email = u.Email) THEN 1
ELSE 2 END as SortMeFirst, *
From Users u
where companyId = 1
order by SortMeFirst
其他提示
将这项工作:
select c.email, *
from Users u
LEFT JOIN companies c on u.email = c.email
where companyid = 1
order by c.email desc
-- order by case when c.email is null then 0 else 1 end
我不知道这是更好的,但它是一种替代方法
select *, (select count(*) from companies where email = u.email) as o
from users u
order by o desc
编辑:是否有可能跨越匹配不同的公司许多电子邮件,而你只是在给定的感兴趣的公司,这成为
select *,
(select count(*) from companies c where c.email = u.email and c.id = 1) as o
from users u
where companyid = 1
order by o desc
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