$ L = \{xyyz\in\{0,1,2\}^{*} : y \neq \epsilon \wedge \exists_{a \in \{0,1,2\}} |y|_a \equiv 0 \}$

I think this languages is regular. I write regular expression: $(1 + 2 + 0) ^ {*} (11 + 22 + 1212 + 2121) (1 + 2 + 0) ^ {*} \cup (1 + 2 + 0) ^ {*} (11 + 00+ 1010 + 0101) (1 + 2 + 0) ^ {*} \cup (1 + 2 + 0) ^ {*} (00 + 22 + 0202 + 2020) (1 + 2 + 0) ^ {*}$

Can someone check out my answer?

没有正确的解决方案

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