Simplifying the Boolean expression $A + \bar{A}\bar{B}$?
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06-11-2019 - |
题
So I'm trying to simplify the Boolean expression (1) $A + \bar{A}\bar{B}$.
I noticed that by Karnaugh maps this is equivalent to $A+\bar{B}$, and I also noticed that if I take the complement of (1), I get ~(1)= $\bar{A}(A + B) = \bar{A}A + \bar{A}B = \bar{A}B$, so then taking complements again yields (1) = $A + \bar{B}$.
But this feels very ad hoc to me, and makes me feel like I'm missing some key point about how to simplify this expression more systematically.
Any thoughts appreciated.
Thanks.
没有正确的解决方案
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