如何从Django的任何视图中的数据传递到任何模板？

Question

就像一个好一点的编码器，我所有的Django模板继承自base.html文件。现在我想添加一些功能的基础，始终表现出一些有趣的事情。一些用户统计信息或随机职位，或饲料等

所有的我的看法是这样的：

def viewname(request) :
    template_vales = {}
    // Stuff
    return render_to_response('some_file_name.html', template_values)

我怎样才能让这个template_values的值总是填充为我所有的意见呢？我有所有我的看法开始这样做呢？如：

import utils

def viewname(request) :
    template_values = {}
    utils.addDefaults(template_values)
    // Stuff
    return render_to_response('some_file_name.html', template_values)

还是有更好的办法？

Answer 1

您应该使用上下文处理器：

http://docs.djangoproject.com/en/dev/ref /模板/ API /

的http：// WWW .B-list.org /博客/ 2006 /君/ 14 / django的-TIPS-模板上下文处理器/

在我的settings.py，我加了几个功能，通用的标准（见最后两个）：

TEMPLATE_CONTEXT_PROCESSORS = (
  "django.core.context_processors.request",
  "django.core.context_processors.auth",
  "django.core.context_processors.debug",
  "django.core.context_processors.i18n",
  "thetrailbehind.context_processors.canonical_url",
  "thetrailbehind.context_processors.gmapkey",)

在第一个我添加定义了视图的规范网址，和GMAP键之间的第二开关。下面是一个函数：

def gmapkey(request):
  url = request.META['HTTP_HOST']
  key = ""
  if url == "127.0.0.1:8000":
    key = "ABQIAAAAGFSvsJjnPmsGb7IcfqoamBTpH3CbXHjuCVmaTc5MkkU4wO1RRhTaJZRNQLjBhGtJlm6eE4gJtku-Rw"   
  elif url ==  "192.168.11.3:8000":
    key = "ABQIAAAAGFSvsJjnPmsGb7IcfqoamBTm8-wcGRt2V-0p00qdRdGeyDhtGBSRTbk2s1ciA8vzdxGeAnqq6g-F4g"
  elif url ==  "192.168.11.17:7000":
    key="ABQIAAAAmHGaJpkZhJ6huJ93yfaYERTmT93Y0kqi8UE3J2QowoLz6rHdtxTHqeJ0nRoENl5LY5gCqHhRK9Yasg"
  elif url == "192.168.1.200:8000":
    key="ABQIAAAAmHGaJpkZhJ6huJ93yfaYERR5_sKpsr8Ui4YjC4HGOe8xaUDeVhSxGV1r1rIL1OvmVMAGUQBoUK0H2w"
  elif url == "192.168.1.73:8000":
    key = "ABQIAAAAGFSvsJjnPmsGb7IcfqoamBR7_CRKSBu49YjvDOLq_-DZQHSIYBSip9sO5IHlFIoZMtDpVcduFQCnWg"
  elif url == "www.trailbehind.com":
    key="ABQIAAAAGFSvsJjnPmsGb7IcfqoamBQxFGSDsNggDdRtUnAb8L8sJ910FhSKwoOpNaUlGCQIhyl6Dy5Cbyb0lQ"
  elif url == "dev.trailbehind.com":
    key="ABQIAAAAmHGaJpkZhJ6huJ93yfaYERQzqIbhF_xOwOwM1oDO_kQqYhag7BRsoTInq2lBuE7fsgDN2xfyD2IL5A"
  elif url == "trailbehind.com":
    key = "ABQIAAAAGFSvsJjnPmsGb7IcfqoamBQL9YYTGyB2pLTiscy54DOfsaXeHBQqMBmq7UvWAZVenmRMtNr_bo3TMQ"
  elif url == "tenuki.trailbehind.com":
    key = "ABQIAAAAGFSvsJjnPmsGb7IcfqoamBQ5SkJUKVREyqcvaNQJsRscGi2yVhSj0mJSTasDiWec8Awxb_TUxOdElw"
  elif url == "cabin.trailbehind.com":
    key = "ABQIAAAAmHGaJpkZhJ6huJ93yfaYERSU-76xxg1tvy-8taAiiF1qqcGi1xSmjUhmAs_v2XAuGxKX_Y-4-gDP3Q"
  elif url == "ec2-174-129-167-234.compute-1.amazonaws.com":
    key = "ABQIAAAAmHGaJpkZhJ6huJ93yfaYERStHq7nubctzsNDgkYc34LoSNrRNhQVCNy2KFFm2BT1sG2yrXrw38ycNg"

Answer 2

有关此我使用上下文处理器。例如，如果我想获得可变MEDIA_URL对于每个视图，我定义context_processors.py这样的：

def media_url(request):
    from django.conf import settings
    return {'MEDIA_URL': settings.MEDIA_URL}

在settings.py必须具有

TEMPLATE_CONTEXT_PROCESSORS = (
    ....
    'django.core.context_processors.request',
    'myaplication.context_processors.menuitems',
)

鉴于必须具有render_to_response和context_instance=RequestContext(request) 例如：

def my_view(request):
return render_to_response('base.html',{},
                              context_instance=RequestContext(request))