通过参数捕获函数？

Question

我一直在寻找到处都是我来相信除了拥有全球变量之外，我都无法做到这一点，但我相信大师在stackoverflow.com中可以帮助我：

在bash有没有办法通过将参数传递给它来捕获一个函数？
例如，trap <function_name> <arg_1> <arg_2> SIGINT？

Answer 1

trap lets you specify an arbitrary command (or sequence of commands), but you have to pass that command as a single argument. For example, this:

trap 'foo bar baz | bip && fred barney ; wilma' SIGINT

will run this:

foo bar baz | bip && fred barney ; wilma

whenever the shell receives SIGINT. In your case, it sounds like you want:

trap '<function> <arg_1> <arg_2>' SIGINT

Answer 2

Maybe I'm misunderstanding you, but ... this is legal:

trap "cp /etc/passwd $HOME/p" SIGINT
trap 'cp /etc/passwd /tmp/p; echo wooo hoo' SIGINT

Answer 3

I'm not sure I understand correctly what you mean, but if you want to make a signal handler call a function and pass it parameters, trap "function arg1 arg2" SIGNAL should work. For example trap "ls -lh /" INT will cause Ctrl+C in your shell to result in ls -lh / (program with 2 args) being called.