在多列上添加外键

Question

我正在尝试在表的两列上创建一个外键，以指向另一个表的相同列，但我似乎收到错误...

这是我所做的：

CREATE TABLE test2 (
  ID INT NOT NULL AUTO_INCREMENT,  
  col1 INT NOT NULL,
  col2 INT NOT NULL, 
  PRIMARY KEY (ID),
  CONSTRAINT fk FOREIGN KEY (col1, col2)
                REFERENCES test1(ID, ID)
  ON UPDATE CASCADE
  ON DELETE RESTRICT
) ENGINE=InnoDB;

.

但我得到

ERROR 1005 (HY000): Can't create table 'DB.test2' (errno: 150)

如果我只有一列，则正确创建表。

有人可以指出错误的位置？

谢谢 n

Answer 1

Tried it here and got the same error. This works though:

CREATE TABLE test2 (
  ID INT NOT NULL AUTO_INCREMENT,  
  col1 INT NOT NULL,
  col2 INT NOT NULL, 
  PRIMARY KEY (ID),
  CONSTRAINT fk FOREIGN KEY (col1)
                REFERENCES test1(ID)
  ON UPDATE CASCADE
  ON DELETE RESTRICT,
  CONSTRAINT fk2 FOREIGN KEY (col2)
                REFERENCES test1(ID)
  ON UPDATE CASCADE
  ON DELETE RESTRICT

) ENGINE=InnoDB

Yes, I know - your script should work (even if it doesn't seem to make much sense). Yet, I guess this new version is better.

Answer 2

The problem would appear to be that you are specifying the same parent column twice in the same foreign key (i.e, (ID, ID)). The following should work:

Create Table Test1
    (
    PK1 int not null
    , PK2 int not null
    , Primary Key ( PK1, PK2 )
    )

Create Table Test2
    (
    Id int not null Auto_Increment
    , PK1 int not null
    , PK2 int not null
    , Primary Key ( ID )
    , Constraint FK_Test2
        Foreign Key ( PK1, PK2 )
        References Test1( PK1, PK2 )
    )

If it is the case, that you want two columns in a child table referencing the same parent table column, then you must add two foreign key references as shown by rsenna as those represent two independent relations.