根据他们的y位置改变动画片的儿童索引?
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14-11-2019 - |
题
我正在用Flash CS5 / AS 3.0编写一个游戏,它通过基于升序的y位置绘制所有相关的电影剪辑来模拟字段深度,即舞台上较低的东西在舞台上重叠的东西重叠。因此,与具有20的y位置的MovieClip相比,具有y位置的MovieClip将需要具有较低的指数,因此第二个将在第一个的顶部绘制。
我写了一个快速而肮脏的函数只是为了测试它。在痕迹期间,我注意到卡车的指数在临时靠近舞台顶部时击中0,但如果我走得太远,它会从舞台上完全消失。然后跟踪开始生成此错误:
ArgumentError:错误#2025:提供的displayObject必须是呼叫者的子项。
flash.display :: displayObjectContainer / GetChildIndex()
在EICT :: Game / ReorganizedisplayIndexes()
在EICT :: Game / Loop()thetruck是播放器控制的车辆的MovieClip 敌人,锥体,岩石是包含MovieClips的阵列
他们都没有活动侦听器。
.private function ReorganizeDisplayIndexes(): void { var drawableObjects:Array = new Array(); drawableObjects.push(theTruck); drawableObjects = drawableObjects.concat(Enemies, Rocks, Bushes); drawableObjects.sortOn("y", Array.DESCENDING | Array.NUMERIC); drawableObjects.reverse(); trace(collisionLayer.getChildIndex(theTruck)); for (var a:int = collisionLayer.numChildren - 1; a >= 0; a--) { collisionLayer.removeChildAt(a); } for (var i:int = 0; i < drawableObjects.length; i++) { collisionLayer.addChild(drawableObjects[i]); } }
解决方案
Hint: You don't need to remove the child first. When you use addChild()
on an object, it is automatically re-added to the next highest depth.
That said, you'll just need to do something like this:
drawableObjects.sortOn("y");
for each(var i:DisplayObject in drawableObjects)
{
if(i.parent)
i.parent.addChild(i);
}
其他提示
Use setChildIndex instead of removing and re-adding:
for (var a:int = collisionLayer.numChildren - 1; i >= 0; i--)
{
collisionLayer.setChildIndex(drawableObjects[i], i);
}
Also, it's a bit wasteful to first order the sort in descending and then reversing the array. Sort it ascending to begin with!