题
我有以下libev代码:
#include <ev.h>
#include <stdio.h>
#include <errno.h>
#include <sys/socket.h>
#include <resolv.h>
#include <string.h>
#include <stdlib.h>
#include <sys/un.h>
#include <netinet/in.h>
ev_io stdin_watcher;
static void cb(EV_P_ ev_io *w, int revents){
puts ("hello");
//read file here - suggestion due to Ioan
#define BUF_LEN 10
char buf[BUF_LEN];
memset(buf,0,BUF_LEN);
int byte_read;
while( (byte_read = recv(w->fd,buf,BUF_LEN-1,0)) > 0) {
printf("len: %i: %s",byte_read,buf);
memset(buf,0,BUF_LEN);
}
if(-1 == byte_read && EAGAIN != errno) {
perror("recv");
}
close(w->fd);
//ev_io_stop (EV_A_ w);
//ev_unloop (EV_A_ EVUNLOOP_ALL);
}
int main (void){
struct ev_loop *loop = ev_default_loop (0);
int len;
int sd;
sd=socket(AF_UNIX,SOCK_STREAM,0);
struct sockaddr_un address;
//memset(&address,0,sizeof(address));
address.sun_family=AF_UNIX;
strcpy(address.sun_path,"/tmp/mysocket");
unlink(address.sun_path);
len=strlen(address.sun_path)+sizeof(address.sun_family);
int x=bind(sd,(struct sockaddr*)&address,sizeof(address));
printf("%d\n",x);
listen(sd,5);
ev_io_init(&stdin_watcher,cb,sd,EV_READ);
ev_io_start(loop,&stdin_watcher);
ev_loop (loop, 0);
// unloop was called, so exit
return 0;
}
一切工作得很好(几乎)。编译: gcc file.c -lev
, ,并运行 ./a.out
.然后写入套接字 ./a.out
在听吗?: echo "gobblydeegook" | nc -U /tmp/mysocket
.
Hello按预期显示在控制台上。
但是程序调用事件,然后它不断打印"hello"ad-infinitum!我希望它继续监视这个unix套接字的写入。如何做到这一点?
解决方案
当套接字上有数据要读取时,该事件被调用。由于您没有从套接字中删除数据,只需打印"hello",则会再次调用该事件以供您处理数据。
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