需要帮助xmllist在flex中

Question

我有XML，具有以下结构，例如

<root>
    <node flag="false"/>
    <node flag="true"/>
    <node flag="false"/>
    <node flag="false"/>
    <node flag="true">
        <node flag="false"/>
        <node flag="true"/>
        <node flag="false"/>
        <node flag="true"/>
    </node>
    <node flag="true"/>
    <node flag="false">
        <node flag="false"/>
        <node flag="true"/>
        <node flag="false"/>
        <node flag="true"/>
    </node>
    <node flag="false"/>
</root>

.

所有子项都有名称“节点”。我需要的是获得一个XMLLIST（或XML，无论如何），还有相同的层次结构，但仅包含带有标志的节点“true”。

我的例子所需的结果是：

<root>
    <node flag="true"/>
    <node flag="true">
        <node flag="true"/>
        <node flag="true"/>
    </node>
    <node flag="true"/>
</root>

.

使用e4x（不通过循环迭代）有什么好方法吗？我试图做以下事项： xml.node。（@ flag==“true”），但在这种情况下结果是：

<root>
        <node flag="true"/>
        <node flag="true">
            <node flag="false"/> <!--need to kill this node-->
            <node flag="true"/>
            <node flag="false"/> <!--need to kill this node-->
            <node flag="true"/>
        </node>
        <node flag="true"/>
    </root>

.

任何想法？谢谢！

Answer 1

Here a one liner in e4x as you ask :

xml..node.((@flag=="false") && (delete parent().children()[valueOf().childIndex()]))

it delete the node to the current XML so pay attention to have a copy of your current XML.

By the way you should know that e4x just do a loop under the hood, and that one liner will not be faster than a custom loop.

var xml:XML=<root>
    <node id="1" flag="false"/>
    <node id="2" flag="true"/>
    <node id="3" flag="false"/>
    <node id="4" flag="false"/>
    <node id="5" flag="true">
        <node id="5.1" flag="false"/>
        <node id="5.2" flag="true"/>
        <node id="5.3" flag="false"/>
        <node id="5.4" flag="true"/>
    </node>
    <node id="6" flag="true"/>
    <node id="7" flag="false">
        <node id="7.1" flag="false"/>
        <node id="7.2" flag="true"/>
        <node id="7.3" flag="false"/>
        <node id="7.4" flag="true"/>
    </node>
    <node id="8" flag="false"/>
</root>

trace("-- before --")
trace(xml.toXMLString())

xml..node.((@flag=="false") && (delete parent().children()[valueOf().childIndex()])) 

trace("\n-- after --")
trace(xml.toXMLString())

Answer 2

It didn't kill those nodes, cause your condition xml.node.(@flag="true") works only on the direct children of root, you have to make another one for the children of node