我正在检查一下痕迹。如果窗口大小随着在每个段之间发送的ACK量并且它将增加ACK的段的大小,则我知道连接速度慢开始。然而,我的跟踪的开头显示不加起来的数字(下面的屏幕截图)。我不知道是如何计算数据包6的窗口大小,因为数学不加起来与前一个窗口大小和介于之间的ACK。任何人都可以脱掉这个吗?

我也不知道如何发现慢速开始变为拥塞避免。有什么我可以在痕迹中留意吗?

慢开始似乎只能去数据包13所以我应该假设拥塞避免已经拍摄?

http://img10.imageshack.us/f/tcptrace.jpg/

感谢您提供的任何帮助!我真的很感激

有帮助吗?

解决方案

Your sentence starting 'I know' is incorrect, hence your confusion. You are conflating the receive window advertised by the receiver and the congestion window maintained by the sender, which does not appear in packets and which doubles on each ACK during slow start. This is not the place to reiterate all of RFC 2001 but I suggest you take another look at it.

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