如何使用abaddressboopcopyArrayofallpeopleinsourcewithsortorpering（）从Expectiongal来源获得人们的数量

Question

我试图在我的iOS 4地址簿的三个来源（1个MobileMe源和2 * Expancegal来源）中获取人员。
NSLog语句始终返回0人为Erganggal，但返回MobileMe的人数。
通过使用abaddressbookcopyArrayofOrcoSocous（地址簿）从iOS地址簿获取所有来源后，我试图通过源迭代来源来为每个源获得更多信息。
我是我使用AbaddressBookCopyArrayofallpeopleinsourceWithsortorderderdrations？
期待不同地址簿来源的所有人的计数。

-(void)countPeopleInSources
{
    ABAddressBookRef addressBook = ABAddressBookCreate();
    CFArrayRef allSources = ABAddressBookCopyArrayOfAllSources(addressBook);
    for (CFIndex i = 0; i < CFArrayGetCount(allSources); i++) 
    {
        ABRecordRef source = (ABRecordRef)CFArrayGetValueAtIndex(allSources, i);
        NSNumber *sourceTypeRef = (NSNumber *)((CFNumberRef)ABRecordCopyValue(source, kABSourceTypeProperty));
        ABPersonSortOrdering sortOrdering = ABPersonGetSortOrdering();
        int sourceType = [sourceTypeRef intValue];
        switch (sourceType) {
        case kABSourceTypeCardDAV:
            NSLog(@"SourceTypeCardDAV");
            break;
        case kABSourceTypeCardDAVSearch:
            NSLog(@"SourceTypeCardDAVSearch");
            break;
        case kABSourceTypeExchange:
            NSLog(@"SourceTypeExchange");
            break;
        case kABSourceTypeExchangeGAL:
            NSLog(@"SourceTypeExchangeGAL");
            break;
        case kABSourceTypeLDAP:
            NSLog(@"SourceTypeLDAP");
            break;
        case kABSourceTypeLocal:
            NSLog(@"SourceTypeLocal");
            break;
        case kABSourceTypeMobileMe:
            NSLog(@"SourceTypeMobileMe"); 
            break;
        default:
            break;
    }
        CFArrayRef allPeopleInSource = ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressBook, source, sortOrdering );
        NSLog(@"Count allPeopleInSource: %i", CFArrayGetCount(allPeopleInSource));

        [sourceTypeRef release];
    }
}

.

编辑FeB24： 它看起来像代码有效，但我有一个问题让人们从埃恩万宝数学。 anyoune成功地从Exchaneggal检索了人们吗？
Mobileme来源回报了人们数目。
这是来自控制台的日志：

2011-02-24 07:04:32.578 Contacts[10099:307] SourceTypeExchangeGAL
2011-02-24 07:04:32.593 Contacts[10099:307] Count allPeopleInSource: 0
2011-02-24 07:04:32.597 Contacts[10099:307] SourceTypeMobileMe
2011-02-24 07:04:32.641 Contacts[10099:307] Count allPeopleInSource: 151
2011-02-24 07:04:32.646 Contacts[10099:307] SourceTypeExchangeGAL
2011-02-24 07:04:32.652 Contacts[10099:307] Count allPeopleInSource: 0

.

Answer 1

Try Using:

ABRecordRef sourceWithType (ABSourceType mySourceType)
{
ABAddressBookRef addressBook = ABAddressBookCreate();
CFArrayRef sources = ABAddressBookCopyArrayOfAllSources(addressBook);
CFIndex sourceCount = CFArrayGetCount(sources);
ABRecordRef resultSource = NULL;
for (CFIndex i = 0 ; i < sourceCount; i++) {
    ABRecordRef currentSource = CFArrayGetValueAtIndex(sources, i);
    ABSourceType sourceType = [(NSNumber *)ABRecordCopyValue(currentSource, kABSourceTypeProperty) intValue];
    if (mySourceType == sourceType) {
        resultSource = currentSource;
        break;
    }
}

return resultSource;
}

ABRecordRef localSource()
{
    return sourceWithType(kABSourceTypeLocal);
}

ABRecordRef exchangeSource()
{
     return sourceWithType(kABSourceTypeExchange);
}

ABRecordRef mobileMeSource()
{
     return sourceWithType(kABSourceTypeMobileMe);
}

You might find this helpful :abaddressbook-absource-and-absourcetype

Answer 2

Are the people you're expecting to return actually in your addressbook? You shouldn't expect ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering() to return the entire GAL. That would be massive. You should only expect it to return a subset of ABAddressBookCopyArrayOfAllPeople().