如何使用Mochijson编码一系列对象？

Question

我有两个对象，我想捆绑在一个数组中，用Mochijson编码为JSON。它们是：

> Book0 = {struct, [{"title", "a book"}, {"id", "1"}]}.      
> Book1 = {struct, [{"title", "another book"}, {"id", "2"}]}.

.

但是，

> mochijson:encode({struct, [{"books", [Book0, Book1]}]}).
** exception exit: {json_encode,{bad_char,{struct,[{"title","a book"},
                                                   {"id","1"}]}}}
     in function  mochijson:json_encode_string_unicode_1/1 (src/mochijson.erl, line 203)
     in call from mochijson:json_encode_string_unicode/1 (src/mochijson.erl, line 190)
     in call from mochijson:'-json_encode_proplist/2-fun-0-'/3 (src/mochijson.erl, line 151)
     in call from lists:foldl/3 (lists.erl, line 1197)
     in call from mochijson:json_encode_proplist/2 (src/mochijson.erl, line 154)

.

如何为Mochijson构建数据？我知道这个文章可悲的是，不涵盖物体阵列。

Answer 1

mochijson：编码（{struct，[{{“books”，{ array ，[book0，book1]}]）。

[123,"\"books\"",58,
 [91,
  [123,"\"title\"",58,"\"a book\"",44,"\"id\"",58,"\"1\"",125],
  44,
  [123,"\"title\"",58,"\"another book\"",44,"\"id\"",58,
   "\"2\"",125],
  93],
 125]

.

但普遍的共识似乎是：“使用Mochijson2”（这将正确地为两种带有和不含生成的情况工作）。

Answer 2

最好的答案，经过一点源潜水，是：更喜欢Mochijson2，除非你有一个不错的原因。

Answer 3

mochijson2也更快，然后是mochijson。