题
如何使用log4cpp的单个字符串登录?
e.g。如果我想将所有argv记录到主要:
#include <iostream>
#include <log4cpp/Category.hh>
#include <log4cpp/FileAppender.hh>
#include <log4cpp/PatternLayout.hh>
using namespace std;
int main(int argc, char* argv[]) {
log4cpp::Appender *appender = new log4cpp::FileAppender("FileAppender","mylog");
log4cpp::PatternLayout *layout = new log4cpp::PatternLayout();
layout->setConversionPattern("%d: %p - %m %n");
log4cpp::Category& category = log4cpp::Category::getInstance("Category");
appender->setLayout(layout);
category.setAppender(appender);
category.setPriority(log4cpp::Priority::INFO);
category.info("program started"); // this works fine, I see it in the logfile
for(int i=0; i<argc; ++i) {
// next line does not compile:
category.info("argv["<<i<<"] = '"<<argv[i]<<"'");
}
return 0;
}
.
线
category.info("argv["<<i<<"] = '"<<argv[i]<<"'");
.
不编译。显然,记录器不起作用为 ostream 。什么是 log4cpp的方式以这样的方式记录,一次优选?
解决方案
You have two options:
-
for (int i = 0; i < argc; ++i) { category.info("argv[%d] = '%s'", i, argv[i]); }
Use
infoStream()
:for (int i = 0; i < argc; ++i) { category.infoStream() << "argv[" << i << "] = '" << argv[i] << "'"; }
I'd go with the latter.
不隶属于 StackOverflow